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x - 4,6 = 8,3 - 3 x - 1/2 = -2/4
x - 4,6 = 5,3 x = -2/4 + 1/2
x = 5,3 + 4,6 x = 0
x = 9,9
\(\text{#}Irumaa:\)\(3\)
\(x - 4,6 = 8,3 - 2 × 1,5\)
\( x - 4,6 = 8,3 - 3\)
\( x - 4,6 = 5,3\)
\( x = 5,3 + 4,6\)
\( x = 11,1\)
\(--------------------------\)
\(x-\dfrac{1}{2}=-\dfrac{3}{4}:\dfrac{3}{2}\)
\(x-\dfrac{1}{2}=-\dfrac{3}{4\text{ }}\text{×}\dfrac{2}{3}\)
\(x-\dfrac{1}{2}=-\dfrac{1}{2}\)
\(x=-\dfrac{1}{2}+\dfrac{1}{2}\)
\(x=0\)
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\(-\dfrac{3}{19}-\dfrac{3}{4}+\dfrac{22}{19}-\dfrac{1}{4}=\left(-\dfrac{3}{19}+\dfrac{22}{19}\right)+\left(-\dfrac{3}{4}-\dfrac{1}{4}\right)=\dfrac{19}{19}-\dfrac{4}{4}=1-1=0\)
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S dau tien ne ta có (2016-1):2=1007,5 => ghép được 1007 cap va thua ra 1 so
ta có :(1-2)+(3-4)+........+(2015-2016)+2014
=-1+-1+-1+......+-1+2014
=-1007+2014=1007
B=1+3+3^2+3^3+...+3^100
3B=3+3^2+3^3+3^4+...+3^101
3B-B=3+3^2+3^3+3^4+...+3^101-1-3-3^2-3^3-...-3^100
2B=3^101-1
B=(3^101-1):2
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\(\dfrac{-2}{3}\cdot\dfrac{5}{7}+\dfrac{5}{7}:\dfrac{3}{4}-1=\dfrac{-2}{3}\cdot\dfrac{5}{7}+\dfrac{5}{7}\cdot\dfrac{4}{3}-1=\left(\dfrac{-2}{3}+\dfrac{4}{3}\right)\cdot\dfrac{5}{7}-1=\dfrac{2}{3}\cdot\dfrac{5}{7}-1=\dfrac{10}{21}-1=-\dfrac{11}{21}\)
−2 / 3⋅5 / 7+5 / 7:3 / 4−1=−2 / 3⋅5 / 7+5 / 7⋅4 / 3−1=(−2 / 3+4 / 3)⋅5 /. 7−1=2 / 3⋅5 / 7−1=10 / 21−1=−11 / 21
nha
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\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
`x - 1 / 2 = [-3] / 4 : 3 / 2`
`x - 1 / 2 = [-3] / 4 . 2 / 3`
`x - 1 / 2 = [-1] / 2`
`x = [-1] / 2 + 1 / 2`
`x = 0`
x-1/2=-1/2
x=-1/2+1/2
x=0