Question

[Trần Thị Ái My]

giải giúp tôi

Answer 1

[Yen Nhi]

Answer:

Bài 1:

a) \(P=\left\{\pm1;\pm2;\pm4;\pm8\right\}\)

b) \(\left\{\pm4;\pm8\right\}\)

Bài 2:

\(21.10+21.89+21\)

\(=21.\left(10+89+1\right)\)

\(=21.100\)

\(=2100\)

\(80-\left(3.2^3-4.5^2\right)\)

\(=80-\left(24-100\right)\)

\(=156\)

\(\left(-12\right)+83+\left(-48\right)+17\)

\(=[\left(-12\right)+\left(-48\right)]+\left(83+17\right)\)

\(=40\)

\(175-[\left(67+197\right)+33]:\left(11.3^2\right)\)

\(=175-297:99\)

\(=172\)

Bài 3:

\(6-2x=12\)

\(\Rightarrow2x=-6\)

\(\Rightarrow x=-3\)

\(2.3^x=10.3^{12}+8.27^4\)

\(\Rightarrow2.3^x=10.3^{12}+8.3^{12}\)

\(\Rightarrow2.3^x=3^{12}.\left(10+8\right)\)

\(\Rightarrow2.3^x=3^{12}.3^2.2\)

\(\Rightarrow3^x=3^{14}\)

\(\Rightarrow x=14\)