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1: x-36:18=12
nên x-2=12
hay x=14
3: 440+2(125-x)=546
nên 2(125-x)=106
\(\Leftrightarrow125-x=53\)
hay x=72
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1000 ! .( 456 . 789789 - 789 . 456456 )
= 1000 ! x ( 456 x 789 x 1001 - 789 x 456 x 1001 )
= 1000 ! x 0 = 0
1000 ! .( 456 . 789789 - 789 . 456456 )
= 1000 ! x ( 456 x 789 x 1001 - 789 x 456 x 1001 )
= 1000 ! x 0 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a) A={-6;-4;-3;-2;-1;0;1;2;3;4;6;8}
b) B={-15;-10;-5;0;5;10;15;20;25;30}
c) C={120;144;168;192}
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: Ta có: \(815-x-145=456\)
\(\Leftrightarrow670-x=456\)
hay x=214
b: Ta có: \(9090:\left[120-x+10\right]=101\)
\(\Leftrightarrow130-x=90\)
hay x=40
c: Ta có: \(528+22\cdot9=22x-198\)
\(\Leftrightarrow22x=924\)
hay x=42
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\(1\\ a,=\left(452+1348\right)+\left(375+25\right)\\ =1800+400=2200\\ b,=50\left(12+15+63\right)=50\cdot90=4500\\ c,=\left(479-474\right)+\left(925-920\right)=5+5=10\\ d,=\left(100-95\right)+\left(90-85\right)+\left(85-80\right)+\left(80-75\right)+\left(70-65\right)+\left(60-55\right)\\ =5+5+5+5+5+5=30\)
\(a,456-\left(x+23\right)=326\\ \Rightarrow x+23=130\\ \Rightarrow x=107\\ b,\left(5x-15\right)\left(x-4\right)=0\\ \Rightarrow5\left(x-3\right)\left(x-4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\\ c,89-\left(x-1\right)^3=62\\ \Rightarrow\left(x-1\right)^3=27=3^3\\ \Rightarrow x-1=3\Rightarrow x=4\\ d,x^5-4x^3=0\\ \Rightarrow x^3\left(x-2\right)\left(x+2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
D={1,4,7,10,...}
tóm lại chúng cách nhau 3 đơn vị