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Bài 1:
uses crt;
var c:aray[1..200]of integer;
i,vt1,vt2:integer;
begin
clrscr;
for i:=1 to 200 do
begin
write('C[',i,']='); readln(c[i]);
end;
for i:=1 to 200 do
if c[i]>0 then
begin
vt1:=i;
break;
end;
if vt1=0 then writeln('Khong co so duong trong day')
else writeln('So duong dau tien trong day la: ',c[vt1],' va chi so cua no la: ',vt1);
for i:=200 downto 1 do
if c[i]>0 then
begin
vt2:=i;
break;
end;
if vt2=0 then writeln('Khong co so duong trong day')
else writeln('So duong cuoi cung trong day la: ',c[vt2],' va vi tri cua no la: ',vt2);
readln;
end.
Bài 1:
#include <bits/stdc++.h>
using namespace std;
long long x,n,i,t;
int main()
{
cin>>n;
t=0;
for (i=1; i<=n; i++)
{
cin>>x;
if ((x<0) and (x%2!=0)) t=t+x;
}
cout<<t;
return 0;
}
#include <iostream>
using namespace std;
int main() {
int x, y;
cin >> x >> y;
int temp = x;
x = y;
y = temp;
cout << "x=" << x << endl;
cout << "y=" << y << endl;
return 0;
}
#include <bits/stdc++.h>
using namespace std;
long long n,i,x,t;
int main()
{
cin>>n;
t=0;
for (i=1; i<=n; i++)
{
cin>>x;
t=t+x;
}
cout<<sqrt(t);
return 0;
}
Câu 1:
uses crt;
var a:array[1..100]of integer;
i,n:integer;
begin
clrscr;
readln(n);
for i:=1 to n do readln(a[i]);
for i:=1 to n do
if a[i] mod 3=0 then write(a[i]:4);
readln;
end.
Câu 2:
uses crt;
var a:array[1..100]of integer;
i,n:integer;
begin
clrscr;
readln(n);
for i:=1 to n do readln(a[i]);
writeln('Cac phan tu chan la: ');
for i:=1 to n do
if a[i] mod 2=0 then write(a[i]:4);
writeln;
writeln('Cac phan tu co chi so le la: ');
for i:=1 to n do
if i mod 2=1 then write(a[i]:4);
readln;
end.
Câu 1:
uses crt;
const fi='bai1.inp';
var f1:text;
a,b:real;
begin
clrscr;
assign(f1,fi); reset(f1);
readln(f1,a,b);
writeln(a*b:4:2);
close(f1);
readln;
end.
Câu 2:
const fi='bai2.inp';
fo='bai2.out';
var f1,f2:text;
a,b:real;
begin
assign(f1,fi); reset(f1);
assign(f2,fo); rewrite(f2);
readln(f1,a,b);
writeln(f2,a*b:4:2);
close(f1);
close(f2);
end.
uses crt;
var st:string;
i,d,t,x,y,kq,j,lt:integer;
begin
clrscr;
readln(st);
d:=length(st);
kq:=0;
for i:=1 to d do
begin
lt:=1;
for j:=1 to d-i do
begin
val(st[i],x,y);
lt:=lt*x;
end;
kq:=kq+x*lt;
end;
writeln(kq);
readln;
end.