Question

[Vũ Hoàng]

`A=(63/9.18 + 21/14.17) : (14/9.13 + 14/14.18 + 14/3.17)`

Answer 1

[Nguyễn Lê Phước Thịnh]

a) Ta có: \(A=\left(\dfrac{63}{9\cdot18}+\dfrac{21}{14\cdot17}\right):\left(\dfrac{14}{9\cdot13}+\dfrac{14}{14\cdot18}+\dfrac{14}{3\cdot17}\right)\)

\(=\left(7\cdot\dfrac{9}{9\cdot18}+7\cdot\dfrac{3}{14\cdot17}\right):\left(14\left(\dfrac{1}{9\cdot13}+\dfrac{1}{14\cdot18}+\dfrac{1}{3\cdot17}\right)\right)\)

\(=\dfrac{7\left(\dfrac{1}{9}-\dfrac{1}{18}+\dfrac{1}{14}-\dfrac{1}{17}\right)}{14\cdot\dfrac{1}{4}\cdot\left(\dfrac{4}{9\cdot13}+\dfrac{4}{3\cdot17}+\dfrac{4}{14\cdot18}\right)}\)

\(=\dfrac{\dfrac{1}{9}-\dfrac{1}{18}+\dfrac{1}{14}-\dfrac{1}{17}}{\dfrac{1}{2}\left(\dfrac{1}{9}-\dfrac{1}{13}+\dfrac{1}{3}-\dfrac{1}{17}+\dfrac{1}{14}-\dfrac{1}{18}\right)}\)

\(=\dfrac{\dfrac{73}{1071}}{\dfrac{1}{2}\cdot\dfrac{4519}{13923}}=\dfrac{1898}{4519}\)