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a: \(\Leftrightarrow4\left(2x+1\right)-3\left(6x-1\right)=2x+1\)
=>8x+4-18x+3=2x+1
=>-10x+7=2x+1
=>-12x=-6
hay x=1/2
b: \(\Leftrightarrow4x^2-12x+7x-21-x^2=3x^2+6x\)
=>5x-21=6x
=>-x=21
hay x=-21
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Lời giải:
b.
$3x+1=5x+2$
$\Leftrightarrow 1-2=5x-3x$
$\Leftrightarrow -1=2x\Leftrightarrow x=\frac{-1}{2}$
d.
$6x-4=7-5x$
$\Leftrightarrow 6x+5x=4+7$
$\Leftrightarrow 11x=11\Leftrightarrow x=1$
f.
$x-12+4x=25+2x-1$
$\Leftrightarrow 5x-12=24+2x$
$\Leftrightarrow 5x-2x=24+12$
$\Leftrightarrow 3x=36$
$\Leftrightarrow x=12$
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Bài 1:
c) ĐKXĐ: \(x\notin\left\{\dfrac{1}{4};-\dfrac{1}{4}\right\}\)
Ta có: \(\dfrac{3}{1-4x}=\dfrac{2}{4x+1}-\dfrac{8+6x}{16x^2-1}\)
\(\Leftrightarrow\dfrac{-3\left(4x+1\right)}{\left(4x-1\right)\left(4x+1\right)}=\dfrac{2\left(4x-1\right)}{\left(4x+1\right)\left(4x-1\right)}-\dfrac{6x+8}{\left(4x-1\right)\left(4x+1\right)}\)
Suy ra: \(-12x-3=8x-2-6x-8\)
\(\Leftrightarrow-12x-3-2x+10=0\)
\(\Leftrightarrow-14x+7=0\)
\(\Leftrightarrow-14x=-7\)
\(\Leftrightarrow x=\dfrac{1}{2}\)(nhận)
Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)
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a: =>3,6-1,7x=2,3-1,4-4=0,9-4=-3,1
=>1,7x=6,7
hay x=67/17
b: \(\Leftrightarrow30\left(5x+4\right)-15\left(3x+5\right)=24\left(4x+9\right)-40\left(x-9\right)\)
=>150x+120-45x-75=96x+216-40x+360
=>105x+45=56x+576
=>49x=531
hay x=531/49
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\(\left(6x+7\right)\left(4x+1\right)\left(x+1\right)=6\)
\(24x^3+58x^2+41x+7=6\)
\(24x^3+58x^2+41x+1=0\)
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