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4x + 3 + 4x = 1040
4x . 43 + 4x . 1 = 1040
4x ( 43 + 1 ) = 1040
4x . 65 = 1040
4x = 1040 : 65 = 16 = 42
Vậy x = 2
\(4^{x+3}+4^x=1040\)
\(\Leftrightarrow4^x\left(1+4^3\right)=1040\)
\(\Leftrightarrow4^x.65=1040\)
\(\Leftrightarrow4^x=16\)
\(\Leftrightarrow x=2\)
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Giả sử đề yêu cầu tìm x là số nguyên
a) Để (3x + 2) ⋮ x thì 2 ⋮ x
⇒ x ∈ Ư(2) = {-2; -1; 1; 2}
b) Để (4x + 7) ⋮ x thì 7 ⋮ x
⇒ x ∈ Ư(7) = {-7; -1; 1; 7}
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\(\frac{1}{2}\times\left(x-\frac{4}{5}\right)+\frac{3}{4}x=\frac{5}{12}\)
\(\Leftrightarrow\frac{1}{2}x-\frac{2}{5}+\frac{3}{4}x=\frac{5}{12}\)
\(\Leftrightarrow\frac{1}{2}x+\frac{3}{4}x=\frac{5}{12}+\frac{2}{5}\)
\(\Leftrightarrow\frac{5}{4}x=\frac{49}{60}\)
\(\Leftrightarrow x=\frac{49}{75}\)
Vậy \(x=\frac{49}{75}\)
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\(-\frac{1}{4}x+\frac{3}{2}x-\frac{2}{3}x+6=\)\(0\)
\(\Rightarrow\)\(-\frac{1}{4}x+\frac{3}{2}x-\frac{2}{3}x\)\(=-6\)
\(\Rightarrow\)\(x\left(-\frac{1}{4}+\frac{3}{2}-\frac{2}{3}\right)\)\(=-6\)
\(\Rightarrow\)\(x.\frac{7}{12}\)\(=-6\)
\(\Rightarrow\)\(x\)\(=-\frac{72}{7}\)
\(\text{Học tốt!!!}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tham khảo:Tìm x thuộc N , biết:a) 2x + 2x+3 =144b) (4x -1)2 =25 x 9 - Hoc24
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\(\dfrac{3x-4}{4}=\dfrac{4x-8}{5}\)
\(\Leftrightarrow\dfrac{3x-4}{4}-\dfrac{4x-8}{5}=0\)
\(\Leftrightarrow\dfrac{5\left(3x-4\right)}{20}-\dfrac{4\left(4x-8\right)}{20}=0\)
\(\Leftrightarrow\dfrac{15x-20}{20}-\dfrac{16x-32}{20}=0\)
\(\Leftrightarrow\dfrac{15x-20-16x+32}{20}=0\)
\(\Leftrightarrow\dfrac{x-12}{20}=0\)
\(\Leftrightarrow x-12=0\)
\(\Leftrightarrow x=12\)
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4x + 5 : 3 - 121 : 11
=4 . 4 + 5 : 3 - 121 : 11
= 16 + \(\frac{5}{3}\) - 11
= \(\frac{20}{3}\)