![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(125^4:5^8\)
\(=\left(5^3\right)^4:5^8\)
\(=5^{12}:5^8\)
\(=5^{12-8}\)
\(=5^4\)
\(=625\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`@` `\text {Ans}`
`\downarrow`
`100^6 * 1000^5 * 10000^3`
`= (10^2)^6 * (10^3)^5 * (10^4)^3`
`= 10^12 * 10^15 * 10^12`
`=`\(10^{12+15+12}=10^{39}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:A=\(2+2^2+2^3+...+2^{60}\)
+)A=\(2.\left(1+2+2^2+...+2^{59}\right)\)
\(\Rightarrow\)\(A⋮2\)
+)A=\(\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{59}+2^{60}\right)\)
A=\(2.\left(1+2\right)+2^3.\left(1+2\right)+...+2^{59}.\left(1+2\right)\)
A=\(2.3+2^3.3+...+2^{59}.3\)
\(\Rightarrow A⋮3\)
Mà 2;3 là 2 số nguyên tố cùng nhau
\(\Rightarrow A⋮2.3\)
\(\Rightarrow A⋮6\)
Học tốt nha!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
=81*(27+9^15):(3^5+3^32)
\(=\dfrac{3^4\cdot\left(3^3+3^{30}\right)}{3^5+3^{32}}=\dfrac{3^7\left(1+3^{27}\right)}{3^5\left(1+3^{27}\right)}=\dfrac{3^7}{3^5}=9\)
=(36/18)^5=2^5=32
`@` `\text {Ans}`
`\downarrow`
`36^5 \div 18^5`
`= (36 \div 18)^5`
`=2^5`
`= 32`
____
`@` Chia lũy thừa cùng số mũ:
\(a^m\div b^m=\left(a\div b\right)^m\)