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(2x2 + 1)(x-3)=0
\(\Rightarrow\orbr{\begin{cases}2x^2+1=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x^2=-1\Rightarrow x^2=-\frac{1}{2}\left(vl\right)\\x=3\end{cases}}\)
Vậy x=3
48-(15-x)5=48
(15-x)5=48-48
(15-x)5=0
=> 15-x =0
x =15-0
x =15
Vậy x=15
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\(a,2^{x+1}=32\\ 2^{x+1}=2^5\\ x+1=5\\ x=4\\ b,2^{2x}+2^{2x+1}=48\\ 2^{2x}+2\cdot2^{2x}=48\\ 3\cdot2^{2x}=48\\ 2^{2x}=16\\ 2^{2x}=2^4\\ 2x=4\\ x=2\)
\(c,3^x+5\cdot3^{x+1}=144\\ 3^x+15\cdot3^x=144\\ 16\cdot3^x=144\\ 3^x=9\\ 3^x=3^2\\ x=2\\ d,3^{x+5}=9^{x+1}\\ 3^{x+5}=3^{2x+2}\\ x+5=2x+2\\ x=3\)
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(2x-48)^3=8 (10.x)^2=0
(2x)^3-48^3=2^3 10^2-x^2=0^2
2.x-48=2 10-x=0
2.x=48:2 x=10-0
2.x=24 x=10-0
x=24:2 x=10
x=12
Tick cho mìn nha ý cuối hình như bn chép sai đề bài đó
(2x - 48)^3 = 8
Ta có (2x-48)3=23
2x-48=2
2x=50
x=25 Vậy x=25
(10-x)^2=0
suy ra 10-x=0
x=10
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1e) Để \(\frac{2x-1}{x-3}\) nguyên thì \(2x-1⋮x-3\)
\(\Leftrightarrow2x-6+5⋮x-3\)
\(\Leftrightarrow2\left(x-3\right)+5⋮x-3\)
Do \(2\left(x-3\right)⋮x-3\) \(\Rightarrow5⋮x-3\)
\(\Rightarrow x-3\in\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow x\in\left\{-2;2;4;8\right\}\)
Vậy:...................
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\(2^{2x}+2^{2x+1}=48\)
\(2^{2x}+2^{2x}.2=48\)
\(2^{2x}.\left(1+2\right)=48\)
\(2^{2x}.3=48\)
\(2^{2x}=48:3\)
\(2^{2x}=16\)
\(2^{2x}=2^4\)
\(\Rightarrow2x=4\)
\(x=4:2\)
\(x=2\)
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\(2^{x+1}-1=63\\ 2^{x+1}=64\\ 2^{x+1}=2^6\\ =>X+1=6\\ =>x=5\)
\(\left(X-3\right)\cdot4^5=4^8\\ X-3=64\\ =>X=67\)
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a) -152 - (3x + 1) = (-2).(-3)3
-152 - 3x - 1 = (-2).(-27)
-3x - 153 = 54
-3x = 54 + 153
-3x = 207
x = -69
b) x - 43 = (35 - x) - 48
x - 43 = 35 - x - 48
x - 43= -x - 13
x = -x - 13 + 43
x = 30 + x
x + x = 30
2x = 30
x = 15
3 x (2x-1)2=48
=> (2x-1)2=48:3
=>(2x-1)2=16
Mà: 42=16 ; (-4)2=16
=> (2x-1)2 =42 hoặc (2x-1)2= (-4)2
=> 2x-1=4 hoặc 2x-1= -4
=> x= 2,5 hoặc x= -2,5
3 x ( 2x - 1 )2 = 48
=> ( 2x - 1 )2 = 48 : 3
=> ( 2x - 1 )2 = 16
=> ( 2x - 1 )2 = 42
=> 2x - 1 = 4 hoặc 2x - 1 = -4
+) 2x - 1 = 4
=> 2x = 5
=> x = 5/2
+) 2x - 1 = -4
=> 2x = -3
=> x = -3/2
Vậy x = 5/2 hoặc x = -3/2