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a/ => 2x - 4 = 22 = 4
=> 2x = 8
=> x = 4
b/ => 60 : 2x = 10
=> 2x = 6
=> x = 3
c/ => 5(2x - 3) = 25
=> 2x - 3 = 5
=> 2x = 8
=> x = 4
d/ => 3x - 6 = 34 : 3 = 33 = 27
=> 3x = 33
=> x = 11
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(231-\left(x-6\right)=1339:13\)
\(\Leftrightarrow231-\left(x-6\right)=103\)
\(\Leftrightarrow x-6=128\)
\(\Leftrightarrow x=134\)
Vậy .....
b, \(70-5\left(2x-3\right)=45\)
\(\Leftrightarrow5\left(2x-3\right)=25\)
\(\Leftrightarrow2x-3=5\)
\(\Leftrightarrow2x=8\)
\(\Leftrightarrow x=4\)
Vậy ....
c, \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ....
d, \(6\left(5x+35\right)=330\)
\(\Leftrightarrow5x+35=55\)
\(\Leftrightarrow5x=20\)
\(\Leftrightarrow x=4\)
Vậy ......
e, \(936-\left(4x+24\right)=72\)
\(\Leftrightarrow4x+24=864\)
\(\Leftrightarrow4x=840\)
\(\Leftrightarrow x=210\)
Vậy ...
231-(x-6)=1339:13
237-x=103
=>x=237-103=134
Vậy x=134
70-5(2x-3)=45
70-10x+15=45
=>-10x=45-15-70=-40
=>x=4
Vậy x=4
Các caau sau tương tự nhé bn
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(70-5\left(2x-3\right)=45\)
\(70-10x+15=45\)
\(-10x=45-70-15\)
\(-10x=-40\)
\(x=4\)
vay \(x=4\)
b) \(156-\left(x+61\right)=82\)
\(x+61=156-82\)
\(x+61=74\)
\(x=74-61\)
\(x=13\)
vay \(x=13\)
c) \(6\left(5x+35\right)=330\)
\(30x+210=330\)
\(30x=330-210\)
\(30x=120\)
\(x=4\)
vay \(x=4\)
d) \(936-\left(4x+24\right)=72\)
\(4x+24=936-72\)
\(4x+24=864\)
\(4x=864-24\)
\(4x=840\)
\(x=210\)
vay \(x=210\)
\(70-5.\left(2x-3\right)\)\(=45\)
\(5.\left(2x-3\right)\)\(=\)\(70-45\)
\(5.\left(2x-3\right)\)\(=25\)
\(2x-3=25:5\)
\(2x-3=5\)
\(2x=8\)
\(x=8:2\)
\(x=4\)
\(156-\left(x+61\right)\)\(=82\)
\(x+61=156-82\)
\(x+61=74\)
\(x=74-61\)
\(x=13\)
\(6.\left(5x+35\right)\)\(=330\)
\(5x+35=330:6\)
\(5x+35=55\)
\(5x=55-35\)
\(5x=20\)
\(x=20:5\)
\(x=4\)
\(936-\left(4x+24\right)\)\(=72\)
\(4x+24=936-72\)
\(4x+24=864\)
\(4x=864-24\)
\(4x=840\)
\(x=840:4\)
\(x=210\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(575-\left(2x+70\right)=445\)
=>\(2x+70=575-445=130\)
=>\(2x=130-70=60\)
=>x=60/2=30
b: \(575-2\left(x+70\right)=445\)
=>\(2\left(x+70\right)=575-445=130\)
=>x+70=130/2=65
=>x=65-70=-5
c: \(x^5=32\)
=>\(x^5=2^5\)
=>x=2
d: \(\left(3x-1\right)^3=8\)
=>\(\left(3x-1\right)^3=2^3\)
=>3x-1=2
=>3x=3
=>\(x=\dfrac{3}{3}=1\)
e: \(\left(x-2\right)^3=27\)
=>\(\left(x-2\right)^3=3^3\)
=>x-2=3
=>x=5
f: \(\left(2x-3\right)^2=9\)
=>\(\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
g: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2\)
=>2x+5=9
=>2x=9-5=4
=>x=4/2=2
h: \(\left(4x-5^2\right)\cdot7^3=7^4\)
=>\(4x-25=\dfrac{7^4}{7^3}=7\)
=>4x=25+7=32
=>\(x=\dfrac{32}{4}=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Phân tích ta được: \(70=2.5.7\)
\(\Rightarrow x=y=z=1\)
\(\Rightarrow x+y+z=1+1+1=3\)
=> Chọn đáp án A
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a) 70 - 5 ( 2x-3 ) = 45
5( 2x-3 ) = 25
2x - 3 = 25 : 5
2x - 3 = 5
2x = 8
x = 8 : 2
x = 4
b) 6 ( 5x + 35 ) = 330
5x + 35 = 330 : 6
5x + 35 = 55
5x = 55 - 35
5x = 20
x = 20 : 5
x = 4
c) 936 - ( 4x + 24 ) = 72
4x + 24 = 936 - 72
4x + 24 = 864
4x = 864 - 24
4x = 840
x = 840 : 4
x = 210
d) 5( 3x + 34 ) = 515
3x + 34 = 515 : 5
3x + 34 = 103
3x = 103 - 34
3x = 69
x = 69 : 3
x = 23
\(a,70-5\left(2x-3\right)=45\)
\(\Leftrightarrow10x-15=70-45\)
\(\Leftrightarrow10x=25+15\)
\(\Leftrightarrow x=\frac{40}{10}=4\)
Vậy x=4
\(b,6\left(5x+35\right)=330\)
\(\Leftrightarrow5x+35=55\)
\(\Leftrightarrow5x=20\)
\(\Leftrightarrow x=4\)
vậy x=4
\(c,936-\left(4x+24\right)=72\)
\(\Leftrightarrow4x+24=936-72\)
\(\Leftrightarrow4x=864-24\)
\(\Leftrightarrow x=840:4=210\)
Vậy x=210
\(d,5\left(3x+34\right)=515\)
\(\Leftrightarrow3x+34=515:5\)
\(\Leftrightarrow3x=103-34\)
\(\Leftrightarrow x=69:3=23\)
Vậy x=23
![](https://rs.olm.vn/images/avt/0.png?1311)
a)13-2(x+1)=7
2.(x+1)=13-7
2.(x+1)=6
x+1=6/2
x+1=3
x=3-1
x=2
a, 13 - 2 ( x + 1 ) = 7
2 .( x + 1 ) = 13 - 7
2 .( x + 1 ) = 6
x + 1 = 6 : 2
x + 1 = 3
x = 3 - 1
x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
\(2^x+6=70\Rightarrow2^x=70-6\Rightarrow2^x=64\)
\(\Rightarrow2^x=2^6\Rightarrow x=6\)
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\(6^x+6=70\Rightarrow6^x=70-6\Rightarrow6^x=64\)
\(\Rightarrow6^x=8^2\)
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