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b) (5/2-3x)=25/9
3x = 5/2-25/9
3x =-5/18
x =-5/18:3
x=-5/54
\(e.\left(x-1\right)^5=-32\)
\(\left(x-1\right)^5=\left(-2\right)^5\)
\(x-1=-2\)
\(x\) \(=-2+1\)
\(x\) \(=-1\)
Vậy \(x=-1\)
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a) 32.x+2=1342176728
32.x=134217728-2
32.x=134217726
x=134217726:32
x=4194303,938
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\(\left(2x-3\right)^2=\frac{9}{4}=\left(\frac{-3}{2}\right)^2=\left(\frac{3}{2}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=\frac{-3}{2}\\2x-3=\frac{3}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=\frac{9}{4}\end{cases}}\)
Vậy \(x=\frac{3}{4}\)hoặc \(x=\frac{9}{4}\)
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Ta có: \(\left(\dfrac{2}{3}x-\dfrac{4}{9}\right)\left(\dfrac{1}{2}-\dfrac{3}{7}x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{3}x=\dfrac{4}{9}\\\dfrac{3}{7}x=\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{7}{6}\end{matrix}\right.\)
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a) \(3^{x+1}=9^x\)
\(\Rightarrow3^{x+1}=\left(3.3\right)^x\)
\(\Rightarrow3^{x+1}=3^{3x}\)
\(\Rightarrow x+1=3x\)
\(\Rightarrow3x-x=2x=1\)
\(\Rightarrow x=1\)
b) \(2^{3x+2}=4^{x+5}\)
\(2^{3x+2}=\left(2.2\right)^{x+5}\)
\(\Rightarrow2^{3x+2}=2^{2\left(x+5\right)}=2^{2x+10}\)
\(\Rightarrow3x+2=2x+10\Rightarrow3x+2=2x+2+8\)
\(\Rightarrow3x=2x+8\Rightarrow3x-2x=8\)
\(\Rightarrow1x=8\Rightarrow x=8\)
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a) \(...\Rightarrow\left\{{}\begin{matrix}x-2=0\\y+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)
b) \(...\Rightarrow|x-2|=|x+3|\Rightarrow\left[{}\begin{matrix}x-2=x+3\\x-2=-x-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}0x=5\\2x=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x\in\varnothing\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\Rightarrow x=-\dfrac{1}{2}\)
c) \(|x-\dfrac{3}{4}|+|x+\dfrac{5}{4}|=1\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{3}{4}\le0\\x+\dfrac{5}{4}\ge0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x\le\dfrac{3}{4}\\x\ge-\dfrac{5}{4}\end{matrix}\right.\)
\(\Rightarrow-\dfrac{5}{4}\le x\le\dfrac{3}{4}\)
=(-8/27)x81+9/8x32. =(-72/3)+36. =36/3. =12