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![](https://rs.olm.vn/images/avt/0.png?1311)
a,xét A:
A=2016x2018
A=2016x(2017+1)
A=2016x1+2016x2017
Xét B:
B=2017x2017
B=2017x(2016+1)
B=2017x2016+2017x1
Vì cả 2 vế Avà B đều có 2017x2016maf 2017x1>2016x1 nên A bé hơn B
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x+23+(-43)+(-23)=x+43+[(-23)+23]=x+43
b)x+(-35)+(-x)+45=[x+(-x)]+(-35)+45=10
c)a+67+(-68)+(-a)=[(-a)+a]+67+(-68)=-1
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm :
\(a,53.11+79.101\)
\(=583+7979\)
\(=8562\)
\(b,45.22+55.23\)
\(=9.5.11.2+55.23\)
\(=55.\left(18+23\right)\)
\(=55.41\)
\(=2255\)
\(c,27.332+68.27+73.332+68.73\)
\(=332.\left(27+73\right)+68.\left(27+73\right)\)
\(=\left(332+68\right).\left(27+73\right)\)
\(=400.100\)
\(=40000\)
Học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= -32 .64 -64.68
= 64.(-32-68)
= 64. -100
= -6400
= 12.23+32.23
=23.(12+32)
=23.44
= 1012
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(-215+\left(-427\right)-\left(-515\right)-573\)
\(=-215+\left(-427\right)+515-573\)
\(=\left(-215+515\right)+\left(-427-573\right)\)
\(=-300+-1000=-1300\)
b) \(-68+68.\left(-76\right)+68.\left(-23\right)\)
\(=68.\left(-1\right)+68.\left(-76\right)+68.\left(-23\right)\)
\(=68.\left(-1+-76+-23\right)\)
\(=68.-10=-6800\)
![](https://rs.olm.vn/images/avt/0.png?1311)
23 - x : 2 + 6 . 10 = 68
23 - x : 2 + 60 = 68
23 - x : 2 = 68 - 60
23 - x : 2 = 8
x : 2 = 23 - 8
x : 2 = 15
x = 15 x 2
x = 30
23 - x : 2 + 6 . 10 = 68
23 - x : 2 + 60 = 68
23 - x : 2 = 68 - 60
23 - x : 2 = 8
x : 2 = 23 - 8
x : 2 = 15
x = 15 x 2
x = 30