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Bài 1:
a) 02002 < 02023
b) 20220 = 20230
c) 549 < 5510
d) ( 4 + 5 )3 > 42 + 52
đ) 92 - 32 > ( 9 - 3 )2
Bài 2:
a) 32 x 43 - 32 + 333
= 9 x 64 - 9 + 333
= 576 - 9 + 333
= 567 + 333
= 900
b) 5 x 43 + 24 x 5 + 410
= 5 x 64 + 24 x 5 + 1
= 5 x ( 64 + 24 ) + 1
= 5 x 88 + 1
= 440 + 1
= 441
c) 23 x 42 + 32 x 5 - 40 x 12023
= 8 x 16 + 9 x 5 - 40 x 1
= 128 + 45 - 40
= 133
Bài 1 :
a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)
b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)
c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)
d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)
đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)
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\(8376:2^2-\left(2^3.5^2-2^3.15\right)+2019^0\)
= \(8376:4-\left(2^3.25-2^3.15\right)+1\)
=\(2094-\left(2^3.\left(25-15\right)\right)+1\)
=\(2094-\left(8.10\right)+1\)
=\(2094-80+1\)
= \(2014+1\)
=\(2015\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(9.x-2.x=\frac{6^{27}}{6^{25}}+\frac{48}{12}\)
\(\Leftrightarrow7x=6^2+4\)
\(\Leftrightarrow7x=36+4=40\)
\(\Leftrightarrow x=\frac{40}{7}\)
Vậy : \(x=\frac{40}{7}\)
b) \(11^x=5.x+\frac{5^{31}}{5^{29}}+3.2^2-10^0\)
\(\Leftrightarrow11^x=5x+5^2+12-1\)
\(\Leftrightarrow11^x=5x+36\)
\(\Rightarrow x\in\varnothing\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2x+2x+1+2x+2+2x+3-480=0
2x+2x.2+2x.22+2x.23=0+480
2x.(1+2+22+23)=480
2x.(1+2+4+8)=480
2x.15=480
2x=480:15
2x=32=25
Vậy x =5
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}-480=0\)
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x.\left(1+2^1+2^2+2^3\right)=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=480:15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy x=5
Chúc bạn học tốt
Ta có :
2x + 2x+2 = 2x+3 - 12 . 20130
=> 2x . ( 1 + 22 ) = 2x+3 - 12 . 1
=> 2x . ( 1 + 4 ) = 2x + 3 - 12
=> 2x . 5 = 2x + 3 - 12
=> 2x+3 - 2x . 5 = 12
=> 2x . ( 23 - 5 ) = 12
=> 2x . ( 8 - 5 ) = 12
=> 2x . 3 = 12
=> 2x = 4
=> 2x = 22
=> x = 2