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![](https://rs.olm.vn/images/avt/0.png?1311)
1992.19911991-1991.19921992
=1992.(1991.1001)-1991.(1992.1001)
=1992.1991.1001-1991.1992.1001
Ta thấy chúng có các thừa số bằng nhau nên chúng bằng nhau nên tích của chúng sẽ giống nhau.
Suy ra: x=0
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\(12,25+\left(-21,37\right)-\left(14,67-21,75\right)\)
\(=12,25-21,37-14,67+21,75\)
\(=12,25+21,75-21,37-14,63-0,04\)
\(=34-36-0,04\)
= -2-0,04=-2,04
![](https://rs.olm.vn/images/avt/0.png?1311)
120:{54-[50:2.(3^2-2.4)]}
= 120:{ 54-[25.(9-8)]}
= 120:{54-[25.1]}
= 120:{54-25}
= 120:29
=\(\dfrac{120}{29}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
g: \(\left(-3\right)^4\cdot10=81\cdot10=810\)
i: \(\left(-2\right)\cdot\left(-2\right)\cdot\left(-4\right)\cdot\left(-4\right)\cdot\left(-4\right)\)
\(=-2\cdot2\cdot4\cdot4\cdot4\)
\(=-2^2\cdot2^2\cdot2^2\cdot2^2=-2^8=-256\)
l: \(26\cdot\left(-125\right)-125\cdot\left(-36\right)\)
\(=125\cdot\left(-26\right)+125\cdot36\)
\(=125\left(-26+36\right)\)
\(=125\cdot10=1250\)
n: \(\left(-37\right)\cdot84+37\cdot\left(-16\right)\)
\(=37\cdot\left(-84\right)+37\cdot\left(-16\right)\)
\(=37\left(-84-16\right)=37\cdot\left(-100\right)=-3700\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: \(45\cdot67+45\cdot34-45\)
\(=45\cdot\left(67+34-1\right)\)
\(=45\cdot100\)
\(=4500\)
![](https://rs.olm.vn/images/avt/0.png?1311)
h: \(\left[\left(-4\right)\cdot\left(-9\right)-6\right]\left[\left(-12\right)-\left(-7\right)\right]\)
\(=\left(36-6\right)\left(-12+7\right)\)
\(=-5\cdot30=-150\)
k: \(125\cdot\left(-24\right)+24\cdot225\)
\(=24\cdot\left(-125\right)+24\cdot225\)
\(=24\left(225-125\right)\)
\(=24\cdot100=2400\)
m: \(\left(-4\right)\cdot13\cdot\left(-250\right)\)
\(=13\cdot4\cdot250\)
\(=13\cdot1000=13000\)
o: \(-43\left(1-296\right)-296\cdot43\)
\(=-43\cdot1+43\cdot296-43\cdot296\)
\(=-43\cdot1=-43\)
![](https://rs.olm.vn/images/avt/0.png?1311)
82 - (45 - 18) - 55
= 82 - 45 + 18 - 55
= (82 + 18) - (45 + 55)
= 100 - 100
= 0
1992x1991x10001-1991x1992x10001
=1992x(10001x1991-10001x1991)
=1992x[10001x(1991-1991)]
=1992x[10001x0]
=1992x0
=0
\(=1992.1991.10001-1991.1992.10001=0\)