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a) A= 100 - 116 : 4
=100-29
=71
b) B= 100 - [ 116 - (13 - 5)2]
=100-[116-82]
=100-(116-64)
=100-52
=48
c) C= |- 65| + (- 42) + |65|
= 65+(-42)+65
= 88
![](https://rs.olm.vn/images/avt/0.png?1311)
\(13\cdot16+13\cdot\left(-116\right)+17\cdot\left(-100\right)\)
\(=13\left(16+-116\right)+17\cdot\left(-100\right)\)
\(=13\cdot\left(-100\right)+17\cdot\left(-100\right)\)
\(=\left(-100\right)\cdot\left(13+17\right)=30\cdot\left(-100\right)=-3000\)
13.16+13.(-116)+17.(-100)
=13.(-116+16)+17.(-100)
=13.(-100)+17.(-100)
=(-100).(13+17)
=-100.30
=(-3000)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(100-\left[116-\left(13-5\right)^2\right]\)
\(=100-\left(116-8^2\right)\)
\(=100-\left(116-64\right)\)
\(=100-52\)
\(=48\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b) /2x-5/=13
=>2x-5=13 hoặc -13
TH1: 2x-5=13 | TH2:2x-5=-13 |
2x=13+5=>2x=18 | 2x=-13+5=>2x=-8 |
x=18:2=>x=9 | x=-8:2=>x=4 |
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Lời giải:
a. $=13-47-13-59+81+35-13$
$=(13-13-13)-(47+59)+(81+35)$
$=-13-106+116=-13+(116-106)=-13+10=-3$
b.
$=345-61+84+61-116-345$
$=(345-345)+(-61+61)-(116-84)$
$=0+0-32=-32$
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\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)
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\(100-\)\(\left[116-\left(13-5^2\right)\right]\)
=\(100-\left[116-\left(13-25\right)\right]\)
=\(100-\left[116-\left(-12\right)\right]\)
=\(100-\left(116+12\right)\)
=\(100-128\)
=\(-28\)
\(100-\left(116-\left(13-5^2\right)\right)=100-\left(116-\left(-12\right)\right)\)
\(=100-\left(116+12\right)=100-128=-28\)
100-[116-(13-52)]
=100-[116-(13-25)]
=100-(116-13+25)
=100-(103+25)
=100-128
=-28