Tính bằng cách thuận tiệ nhất:
a) 2,5 x 8,7 x 4=
b) 2,735 + 1,248 +3,265 + 4,752=
c) 4/13 x 2/3 x 13/4 x 3/2=
Ghi lời giải ra nhé
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B=10/56 + 10/140 + 10/260 +...+10/1400
B=5/28 + 5/70 + 5/130 + ... + 5/700
3B/5=3/4.7 + 3/7.10 + 3/10.13 +...+ 3/25.28
3B/5=1/4 - 1/7 + 1/7 - 1/10 + 1/10 - 1/13 +...+1/25 - 1/28
3B/5=1/4 - 1/28
3B/5=3/14
B=3/14.5/3
B=5/14
Vậy B = 5/14
b là mình thêm vào cho làm dễ bạn bỏ đi nhé
= 2,5 *4 * 8,7 + 0,02 * 500 * 3 ,26
= 10 * 8,7 + 10 * 3 , 26
= 10 * ( 8,7+3,26 ) = 10 * 11, 96
= 119 ,6
Đ mình với nhé !
2,5 x 8,7 x 4 + 0,02 x 3,26 x 500 = 10 x 8,7 + 10x 3,26
= 10 x ( 8,7 + 3,26 )
= 10x 11,96
= 119,6
a) \(\frac{3}{4}\times\frac{1}{2}\times2\)
C1: \(=\frac{3}{8}\times2=\frac{3}{4}\)
C2: \(=\frac{3}{4}\times1=\frac{3}{4}\)
b) \(\left[\frac{3}{4}+\frac{1}{2}\right]\times\frac{5}{7}\)
C1: \(=\frac{5}{4}\times\frac{5}{7}=\frac{25}{28}\)
C2: \(=\frac{3}{4}\times\frac{5}{7}+\frac{1}{2}\times\frac{5}{7}=\frac{15}{28}+\frac{5}{14}=\frac{25}{28}\)
a/\(\frac{3}{4}\cdot\frac{1}{2}\cdot2=\frac{6}{8}\cdot2=\frac{12}{8}=\frac{3}{2}\)
\(\frac{3}{4}\cdot\frac{1}{2}\cdot2=\frac{3}{4}\cdot\frac{2}{2}=\frac{3}{4}\cdot1=\frac{3}{4}\)
b/\(\left(\frac{3}{4}+\frac{1}{2}\right)\cdot\frac{5}{7}=\frac{5}{4}\cdot\frac{5}{7}=\frac{25}{28}\)
\(\left(\frac{3}{4}+\frac{1}{2}\right)\cdot\frac{5}{7}=\frac{3}{4}\cdot\frac{5}{7}+\frac{1}{2}\cdot\frac{5}{7}=\frac{15}{28}+\frac{5}{14}=\frac{15}{28}+\frac{10}{28}=\frac{25}{28}\)
c/\(\frac{5}{7}\cdot\frac{13}{21}+\frac{2}{7}\cdot\frac{13}{21}=\frac{65}{147}+\frac{26}{147}=\frac{91}{147}=\frac{13}{21}\)
\(\frac{5}{7}\cdot\frac{13}{21}+\frac{2}{7}\cdot\frac{13}{21}=\left(\frac{5}{7}+\frac{2}{7}\right)\cdot\frac{13}{21}=1\cdot\frac{13}{21}=\frac{13}{21}\)
Học tốt @#_#@
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{5\times4\times13}{13\times5\times3}=\dfrac{4}{3}\\ b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\dfrac{3}{7}\times\dfrac{7}{5}+\dfrac{5}{2}\times\dfrac{7}{5}=\dfrac{3}{5}+\dfrac{7}{2}=\dfrac{6}{10}+\dfrac{35}{10}=\dfrac{41}{10}\\ c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
2,5 x 9,5 x 4 + 19,5 x 10 = 9,5 x ( 2,5 x 4 ) + 195
= 9,5 x 10 + 195
= 95 + 195
= 290
1,2 + 2,1 + 3,4 + 4,3 + 5,6 + 6,5 +7,8 + 8,7 = ( 1,2 + 7,8 ) + ( 3,4 + 5,6 ) + ( 4,3 + 8,7 ) + ( 2,1 + 6,5 )
= 9 + 9 + 13 + 8,6
= 39,6
a) 2,5 x 8,7 x 4
= 8,7 x (2,5 x 4)
= 8,7 x 10
= 87
b) 2,735 + 1,248 + 3,265 + 4,752
= (2,735 + 3,265) + (1,248 + 4,752)
= 6 + 6 = 12
c) \(\dfrac{4}{13}\times\dfrac{2}{3}\times\dfrac{13}{4}\times\dfrac{3}{2}\)
\(=\dfrac{4}{13}\times\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{3}{2}\)
\(=\dfrac{1}{1}\times\dfrac{1}{1}=\dfrac{1}{1}\)
a) 2,5 x 8,7 x 4
= 2,5 x 4 x 8,7
= 10 x 8,7
= 87
b) 2,735 + 1,248 + 3,265 + 4,752
= 2,735 + 3,265 + 1,248 + 4,752
= 6 + 6
= 12
c) \(\dfrac{4}{13}\times\dfrac{2}{3}\times\dfrac{13}{4}\times\dfrac{3}{2}\)
\(=\dfrac{4}{13}\times\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{3}{2}\)
= 1 x 1
= 1