tính
A = \(\frac{3}{2}\) + \(\frac{3}{10}\) + \(\frac{3}{50}\) + \(\frac{3}{250}\) + \(\frac{3}{1250}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) `1/9-0,3. 5/9+1/3`
`=1/9-3/10 . 5/9+1/3`
`=1/9-15/90+1/3`
`=1/9-1/6+1/3`
`=2/18-3/18+6/18`
`=5/18`
b) `(-2/3)^2+1/6-(-0,5)^3`
`=4/9+1/6-(-0,125)`
`=4/9+1/6+0,125`
`=4/9+1/6+1/8`
`=32/72+12/72+9/72`
`=53/72`
a)
\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)
b)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)
ko chép lại đầu bài nha
=(53x+800):7020=(49x+147):6000
=(53x+800).6000=70
x=145,0369515
lưu ý:mik làm theo cách suy luận nhé @@@
A= \(\frac{3}{2}\)+ \(\frac{3}{10}\)+ \(\frac{3}{50}\)+ \(\frac{3}{250}\)+ \(\frac{3}{1250}\).
A= \(\frac{1875}{1250}\)+ \(\frac{375}{1250}\)+ \(\frac{75}{1250}\)+ \(\frac{15}{1250}\)+ \(\frac{3}{1250}\).
A= \(\frac{2343}{1250}\).
A= 1,8744.
=1833 nha