(X-3)x5=22
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\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)
\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)
\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)
\(=\dfrac{3}{20}\)
\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)
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\(\left(x-12,5\right):\frac{3}{4}=\frac{8}{5}\)
\(x-12,5=\frac{8}{5}.\frac{3}{4}\)
\(x-12,5=\frac{6}{5}\)
\(x=\frac{6}{5}+12,5\)
\(x=\frac{137}{10}\)
\(\left(x-\frac{2}{5}\right)\times\frac{5}{11}=\frac{75}{22}\)
\(x-\frac{2}{5}=\frac{75}{22}:\frac{5}{11}\)
\(x-\frac{2}{5}=\frac{15}{2}\)
\(x=\frac{15}{2}+\frac{2}{5}\)
\(x=\frac{79}{10}\)
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b) Tại x=14 thì:\(B\left(x\right)=x^5-15x^4+16x^3-29x^2+13x\)
\(=x^5-\left(x+1\right)x^4+\left(x+2\right)x^3-\left(2x+1\right)x^2+x\left(x-1\right)\)
\(=x^5-x^5-x^4+x^4+2x^3-2x^3-x^2+x^2-x=-x=-14\)
a) A(x)=1
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Ta có: f(x) + g(x) – h(x)
= (x5 – 4x3 + x2 – 2x + 1) + (x5 – 2x4 + x2 – 5x + 3) – (x4 – 3x2 + 2x – 5)
= x5 – 4x3 + x2 – 2x + 1 + x5 – 2x4 + x2 – 5x + 3 – x4 + 3x2 - 2x + 5
= (x5 +x5) – (2x4 + x4) – 4x3 + (x2 + x2 + 3x2)- (2x + 5x + 2x) + (1 + 3 + 5)
= (1 + 1)x5 – (2 + 1)x4 – 4x3 + (1 + 1 + 3)x2 - (2 + 5 + 2)x + (1 + 3 + 5)
= 2x5 – 3x4 – 4x3 + 5x2 – 9x + 9
(X-3)x5=22
X-3=22:5
X-3=4,4
X=4,4+3
X=7,4
tk nha bạn
thank you bạn
\(\left(x-3\right)x5=22\)
\(x-3=\frac{22}{5}\)
\(x=\frac{22}{5}+3=\frac{22+15}{5}=\frac{37}{5}\)