1+x.x=x
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![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(x\times x+372=472\)
\(x^2=100\)
\(x=10;-10\)
b) \(69,5-x\times x=20,5\)
\(69,5-x^2=20,5\)
\(-x^2+69,5=20,5\)
\(-x^2=-49\)
\(x^2=49\)
\(x=-7;7\)
c) \(x\times x-\dfrac{1}{6}=\dfrac{5}{18}\)
\(x^2=\dfrac{4}{9}\)
\(x=\dfrac{2}{3};-\dfrac{2}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2X : X = X
2 = X
2X + X = 6X
câu này ko biết chắc sai đề
2X * X = 10X
2*X*X=10X
gạch X ở hai vế
ta có
2*X=10
X = 10: 2
X= 5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(3x-1=0\)
\(\Leftrightarrow3x=1\)
\(\Leftrightarrow x=\dfrac{1}{3}\)
Vậy: \(S=\left\{\dfrac{1}{3}\right\}\)
b) Ta có: \(5x-2=x+4\)
\(\Leftrightarrow5x-x=4+2\)
\(\Leftrightarrow4x=6\)
\(\Leftrightarrow x=\dfrac{3}{2}\)
Vậy: \(S=\left\{\dfrac{3}{2}\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x-1\right)\left(x.x+1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(x^2+1\right)=0\)
\(\Rightarrow\left[\begin{matrix}x-1=0\\x^2+1=0\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}x=0+1\\x^2=0-1\end{matrix}\right.\)
\(\Rightarrow x=1\)
\(\left(x-1\right)\left(x.x+1\right)=0\\ < =>\left(x-1\right)\left(x^2+1\right)=0\\ =>\left[\begin{matrix}x-1=0\\x^2+1=0\end{matrix}\right.\\ =>\left[\begin{matrix}x=1\left(nhận\right)\\x^2=-1\left(loại\right)\end{matrix}\right.\\ =>x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x.\left(x-\frac{1}{2}\right)=1+x.x\)
\(x^2-\frac{1}{2}x=1+x^2\)
\(\frac{-1}{2}x=1+x^2-x^2\)
\(\frac{-1}{2}x=1\)
\(\Leftrightarrow x=1:\frac{-1}{2}=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
X=1 hoặc x=2
ai trả lời giùm mình với