51 . 125 - 51 . 42 - 17 . 150/3+6+9+.....+99
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{51.125-51.42-17.150}{3+6+9+...+99}\)=\(\frac{51.125-51.42-17.3.50}{1683}\)=\(\frac{51.125-51.42-71.50}{1683}\)=\(\frac{51\left(125-42-50\right)}{1683}=\frac{51.33}{51.33}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính tử: \(51.125-51.42-17.150\)
\(=51.125-51.42-17.3.50\)
\(=51.125-51.42-51.50\)
\(=51.\left(125-42-50\right)=51.33\)
Tính mẫu:
Số các số hạng: \(\left(99-3\right):3+1=33\)
Mẫu = \(33.\left(\dfrac{99+3}{2}\right)=33.51\)
\(B=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Viết thương của mỗi phép chia sau dưới dạng phân số (theo mẫu).
13 : 17 = \(\dfrac{13}{17}\)
21 : 11 = \(\dfrac{22}{11}\)
40 : 51 = \(\dfrac{40}{51}\)
72 : 25 = \(\dfrac{72}{25}\)
b) Viết (theo mẫu)
34 : 17 = \(\dfrac{34}{17}\) = 2
20 : 5 =\(\dfrac{20}{5}\) = 4
42 : 42 = \(\dfrac{42}{42}\) = 1
0 : 6 = \(\dfrac{0}{6}\) = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
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`@` `\text {Ans}`
`\downarrow`
`2023 \times 14 + 2023 \times 83+97`
`= 2023 \times (14+83) + 97`
`= 2023 \times 97 + 97`
`= 196231 +97`
`= 196328`
`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`
`= 78 \times (31+24+17+22 \times 72)`
`= 78 \times (31+24+17+1584)`
`= 78 \times 1656`
`= 129168`
`371 \times 69+371 \times 14+629 \times 83`
`= 371 \times (69+14) + 629 \times 83`
`= 371 \times 83 + 629 \times 83`
`= 83 \times (371+629)`
`= 83 \times 1000`
`= 83000`
`91 \times 51+49 \times 163-49 \times 72`
`= 91 \times 51 + 49 \times (163-72)`
`= 91 \times 51+49 \times 91`
`= 91 \times (51+49)`
`= 91 \times 100`
`= 9100`
`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`
`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`
`= 9 \times 4 \times (17+81+2)`
`= 36 \times 100`
`= 3600`
`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`
`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`
`= 17 \times 100 + 3486 \times 4815`
`= 1700 + 16785090`
`= 16786790`
![](https://rs.olm.vn/images/avt/0.png?1311)
575-[6x+60]=25
[6x+60]=575-25
[6x+60]=550
suy ra:
6x+60=550 hoặc 6x+60=-550
6x =550-60 6x =-550-60
6x =490 6x =-610
vậy...
[x+32]-17.2=42
[x+32]-17 =42:2
[x+32]-17 =21
[x+32] =21+17
[x+32] =28
suy ra:
x+32=28 hoặc x+32=-28
x =28-32 x =-28-32
x =-4 x =-60
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(-48\right)+127+\left(-52\right)+73\)
\(=\left(-48-52\right)+\left(127+73\right)\)
\(=-100+200\)
\(=100\)
b) \(\left(-38\right)\cdot45+\left(-38\right)\cdot55\)
\(=\left(-38\right)\cdot\left(45+55\right)\)
\(=\left(-38\right)\cdot100\)
\(=-3800\)
c) \(\left(-125\right)+371+\left(-875\right)+629+150\)
\(=\left(-125-875\right)+\left(371+629\right)+150\)
\(=-1000+1000+150\)
\(=150\)
d) \(271+\left(-392\right)+729+\left(-608\right)+\left(-123\right)\)
\(=\left(271+729\right)+\left(-392-608\right)-123\)
\(=1000-1000-123\)
\(=-123\)
e) \(\left(-48\right)\cdot25+25\cdot\left(-52\right)\)
\(=25\cdot\left(-48-52\right)\)
\(=25\cdot-100\)
\(=-2500\)
f) \(47\cdot\left(-11\right)+47\)
\(=47\cdot\left(-11+1\right)\)
\(=47\cdot-10\)
\(=-470\)
g) \(56-7\cdot8+11\)
\(=56-56+11\)
\(=0+11\)
\(=11\)
h) \(-42+51+2+\left(-11\right)+40\)
\(=\left(-42+2\right)+\left(51-11\right)+40\)
\(=-40+40+40\)
\(=0+40\)
\(=40\)
a: =-48-52+127+73
=200-100
=100
b; \(=-38\left(45+55\right)=-38\cdot100=-3800\)
c: \(=-125-875+371+629+150\)
=-1000+1000+150
=150
d: =271+729-392-608-123
=1000-1000-123
=-123
e: =25(-48-52)
=25*(-100)
=-2500
f: =47(-11+1)
=47(-10)
=-470
g: =56-56+11
=11
h: =-42+2+51-11+40
=-40+40+40
=40
\(=\dfrac{17\left(375-126-150\right)}{33\cdot\left(99+3\right):2}=\dfrac{17\cdot99}{33\cdot102:2}=\dfrac{17\cdot3\cdot33}{33\cdot51}=1\)