(-11).36-64.11
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\left(-4\right).\left(-3\right).25.\left(-8\right)\)
\(=12.25.\left(-8\right)\)
\(=12.\left(-200\right)\)
\(=-2400\)
\(b,7.\left(-25\right).\left(-3\right)^2.\left(-4\right)\)
\(=7.\left(-3\right)^2.100\)
\(=7.9.100=63.100\)
\(=6300\)
\(d,\left[93-\left(20-7\right)\right]:16\)
\(=\left[93-13\right]:16\)
\(=80:16=5\)
\(e,51-\left(-51\right)+\left(-53\right)+49\)
\(=51.2-53+49=102-53+49\)
\(=49.2=98\)
\(f,168-49+\left(-68\right)+4\)
\(=168-68-49+4=100-45=55\)
\(g,53-\left(-7\right)+\left(-53\right)-49\)
\(=53+7-53-49\)
\(=7-49=-42\)
\(h,25.\left(-124\right)+124.25\)
\(=25.\left(-124+124\right)\)
\(=25.0=0\)
\(i,\left(-11\right).36-64.11\)
\(=11.\left(-36\right)+\left(-64\right).11\)
\(=11.\left(-36-64\right)=11.\left(-100\right)\)
\(=-1100\)
\(k,125.\left(-24\right)+24.125\)
\(=125.\left(-24+24\right)=125.0=0\)
\(l,125.\left(-23\right)+23.\left(225\right)\)
\(=-125.23+23.225\)
\(=23.\left(-125+225\right)=23.100=2300\)
\(m,-11.36+64.\left(-11\right)\)
\(=-11.\left(36+64\right)=-11.100=-1100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 26 x 11 = 26 x (10 + 1)
= 26 x 10 + 26 x 1 = 260 + 26 = 286
35 x 101 = 35 x (100 + 1)
= 35 x 100 + 35 x 1 = 3500 + 35 = 3535
b) 213 x 11 = 213 x (10 +1)
= 213 x 100 + 213 x 1 = 2130 + 213 = 2343
123 x 101 = 123 x (100 + 1)
= 123 x 100 + 123 x 1
= 12300 + 123 = 12423
Nói thêm: Muốn nhân một số với 11 (hoặc 101) ta nhân số đó với 10 (hoặc 100) rồi cộng thêm chính số đó.
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 21/11 + 19/36 + 11/36 = 21/11 + ( 19/36 + 11/36 ) = 21/11 + 30/36 = 21/11 + 5/6 = 126/66 + 55/66 = 181/66 = \(2\frac{49}{66}\)
Mà \(2\frac{49}{66}< 3\Rightarrow\frac{21}{11}+\frac{19}{36}+\frac{11}{36}< 3\)
Chắc vậy! k cho mình nha!
Ta có: \(\frac{21}{11}-1+\frac{19}{36}-1+\frac{11}{36}-1=\frac{10}{11}-\frac{7}{6}=-\frac{17}{66}< 0.\)
\(\Rightarrow\frac{21}{11}+\frac{19}{36}+\frac{11}{36}< 3lđ.\)
Học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,
= 4.3.25.8
= (4.25).3.8
= 100.24
= 2400
b,
= 7.25.3.3.4
= (25.4).7.3.3
= 100.63
= 6300
d,
= (93-13):16
= 80:16
=5
e,
= 53+51-53+49
= (53-53)+(51+49)
= 0+100
= 100
f,
= 168-49-68+4
= (168-68)+4-49
= 0+4-49
= -45
g,
= 53+7-53-49
= (53-53)+7-49
= 0+7-49
-42
h,
= (-25).124+124.25
= 124.(25-25)
= 124.0
= 0
i,
= 11.(-36)-64.11
= 11.(-36-64)
= 11.(-100)
= -1100
k,
= 125.(24-24)
= 125.0
= 0
l,
= (-125).23+23.225
= 23.(225-125)
= 23.100
= 2300
m,
= (-11).(36+64)
= (-11).100
= -1100
a) (-4).(-3).25.(-8)
= (-4.25).[(-3).(-8)]
=-100.24
=-2400
b) 7.(– 25).(– 3)2.(– 4)
= 7.(-25).9.(-4)
=(7.9).[(-25).(-4)]
=63.100
=6300
d)[ 93–( 20–7 )]:16
= [ 93 - 13]:16
= 80 : 16
= 5
e) 53 – (–51) + (-53) + 49
= 53 + 51 + (-53) + 49
= [53+(-53)] + (51+49)
=0 + 100
=100
f) 168 – (49) + (-68) + 4
= [168+(-68)] + 4 - 49
= 100 + 4 - 49
= 104 - 49
= 55
g) 53 – (–7) + (-53) – 49
= 53 + 7 - 53 - 49
= (53 - 53) + (7 - 49)
= 0 + ( - 42)
= -42
h) 25.(- 124) + 124. 25
= 25.(-124+124)
= 25.0
=0
i) (-11).36 - 64.11
= 11.(-36-64)
= 11.(-100)
= -1100
k) 125.(- 24) + 24.125
=125.(-24+24)
=125.0
=0
l) 125.(-23) + 23.225
=23.(-125+225)
=23.100
=2300
m) (-11).36 + 64.(- 11)
=(-11).(36+64)
=-11.100
=-1100
![](https://rs.olm.vn/images/avt/0.png?1311)
\(18+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-36\right]\)
\(\Leftrightarrow\dfrac{198}{11}+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-\dfrac{396}{11}\right]\)
\(\Leftrightarrow\dfrac{198+x-18}{11}=36+\dfrac{1}{11}\times\dfrac{10x-180-396}{11}\)
\(\Leftrightarrow\dfrac{180+x}{11}=36+\dfrac{10x-576}{121}\)
\(\Leftrightarrow\dfrac{1980+11x}{121}=\dfrac{4356}{121}+\dfrac{10x-576}{121}\)
\(\Leftrightarrow1980+11x=4356+10x-576\)
\(\Leftrightarrow11x-10x=4356-1980-576\)
\(\Leftrightarrow x=1800\)
(-11).36-64.11
= 11.(-36) - 64.11
= 11.(-36 - 64)
= 11.(-100)
= -1100
(-11)*36-64*11
=11*(-36)-64*11
=11*((-36)-64)
=11*(-100)
=-1100
k mik