![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\left(-4\right).\left(-3\right).25.\left(-8\right)\)
\(=12.25.\left(-8\right)\)
\(=12.\left(-200\right)\)
\(=-2400\)
\(b,7.\left(-25\right).\left(-3\right)^2.\left(-4\right)\)
\(=7.\left(-3\right)^2.100\)
\(=7.9.100=63.100\)
\(=6300\)
\(d,\left[93-\left(20-7\right)\right]:16\)
\(=\left[93-13\right]:16\)
\(=80:16=5\)
\(e,51-\left(-51\right)+\left(-53\right)+49\)
\(=51.2-53+49=102-53+49\)
\(=49.2=98\)
\(f,168-49+\left(-68\right)+4\)
\(=168-68-49+4=100-45=55\)
\(g,53-\left(-7\right)+\left(-53\right)-49\)
\(=53+7-53-49\)
\(=7-49=-42\)
\(h,25.\left(-124\right)+124.25\)
\(=25.\left(-124+124\right)\)
\(=25.0=0\)
\(i,\left(-11\right).36-64.11\)
\(=11.\left(-36\right)+\left(-64\right).11\)
\(=11.\left(-36-64\right)=11.\left(-100\right)\)
\(=-1100\)
\(k,125.\left(-24\right)+24.125\)
\(=125.\left(-24+24\right)=125.0=0\)
\(l,125.\left(-23\right)+23.\left(225\right)\)
\(=-125.23+23.225\)
\(=23.\left(-125+225\right)=23.100=2300\)
\(m,-11.36+64.\left(-11\right)\)
\(=-11.\left(36+64\right)=-11.100=-1100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 21/11 + 19/36 + 11/36 = 21/11 + ( 19/36 + 11/36 ) = 21/11 + 30/36 = 21/11 + 5/6 = 126/66 + 55/66 = 181/66 = \(2\frac{49}{66}\)
Mà \(2\frac{49}{66}< 3\Rightarrow\frac{21}{11}+\frac{19}{36}+\frac{11}{36}< 3\)
Chắc vậy! k cho mình nha!
Ta có: \(\frac{21}{11}-1+\frac{19}{36}-1+\frac{11}{36}-1=\frac{10}{11}-\frac{7}{6}=-\frac{17}{66}< 0.\)
\(\Rightarrow\frac{21}{11}+\frac{19}{36}+\frac{11}{36}< 3lđ.\)
Học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a,
= 4.3.25.8
= (4.25).3.8
= 100.24
= 2400
b,
= 7.25.3.3.4
= (25.4).7.3.3
= 100.63
= 6300
d,
= (93-13):16
= 80:16
=5
e,
= 53+51-53+49
= (53-53)+(51+49)
= 0+100
= 100
f,
= 168-49-68+4
= (168-68)+4-49
= 0+4-49
= -45
g,
= 53+7-53-49
= (53-53)+7-49
= 0+7-49
-42
h,
= (-25).124+124.25
= 124.(25-25)
= 124.0
= 0
i,
= 11.(-36)-64.11
= 11.(-36-64)
= 11.(-100)
= -1100
k,
= 125.(24-24)
= 125.0
= 0
l,
= (-125).23+23.225
= 23.(225-125)
= 23.100
= 2300
m,
= (-11).(36+64)
= (-11).100
= -1100
a) (-4).(-3).25.(-8)
= (-4.25).[(-3).(-8)]
=-100.24
=-2400
b) 7.(– 25).(– 3)2.(– 4)
= 7.(-25).9.(-4)
=(7.9).[(-25).(-4)]
=63.100
=6300
d)[ 93–( 20–7 )]:16
= [ 93 - 13]:16
= 80 : 16
= 5
e) 53 – (–51) + (-53) + 49
= 53 + 51 + (-53) + 49
= [53+(-53)] + (51+49)
=0 + 100
=100
f) 168 – (49) + (-68) + 4
= [168+(-68)] + 4 - 49
= 100 + 4 - 49
= 104 - 49
= 55
g) 53 – (–7) + (-53) – 49
= 53 + 7 - 53 - 49
= (53 - 53) + (7 - 49)
= 0 + ( - 42)
= -42
h) 25.(- 124) + 124. 25
= 25.(-124+124)
= 25.0
=0
i) (-11).36 - 64.11
= 11.(-36-64)
= 11.(-100)
= -1100
k) 125.(- 24) + 24.125
=125.(-24+24)
=125.0
=0
l) 125.(-23) + 23.225
=23.(-125+225)
=23.100
=2300
m) (-11).36 + 64.(- 11)
=(-11).(36+64)
=-11.100
=-1100
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\dfrac{5}{7}=\dfrac{5\cdot11}{7\cdot11}=\dfrac{55}{77}\)
\(\dfrac{9}{11}=\dfrac{9\cdot7}{11\cdot7}=\dfrac{63}{77}\)
b: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot9}{7\cdot9}=\dfrac{54}{63}\)
\(-\dfrac{12}{54}=\dfrac{-2}{9}=\dfrac{-2\cdot7}{9\cdot7}=-\dfrac{14}{63}\)
c: \(\dfrac{-11}{30}=\dfrac{-11\cdot4}{30\cdot4}=\dfrac{-44}{120}\)
\(\dfrac{-17}{-40}=\dfrac{17}{40}=\dfrac{17\cdot3}{40\cdot3}=\dfrac{51}{120}\)
d: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot3}{7\cdot3}=\dfrac{18}{21}\)
\(\dfrac{-12}{36}=\dfrac{-1}{3}=\dfrac{-1\cdot7}{3\cdot7}=\dfrac{-7}{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{11}{36}-\dfrac{-7}{24}=\dfrac{22}{72}-\dfrac{-21}{72}=\dfrac{43}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) bằng 79/180
b)bằng 25/72 nha
k cho Jico nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{55}{11}\cdot6+\dfrac{55}{16}\cdot21+\dfrac{55}{21}\cdot26+\dfrac{55}{26}\cdot31+\dfrac{55}{31}\cdot36+\dfrac{55}{36}\cdot41=30+\dfrac{1155}{16}+\dfrac{1430}{21}+\dfrac{1705}{26}+\dfrac{1980}{31}+\dfrac{2255}{36}=\dfrac{12186720}{406224}+\dfrac{29324295}{406224}+\dfrac{27661920}{406224}+\dfrac{26638920}{406224}+\dfrac{25945920}{406224}+\dfrac{25445420}{406224}=\dfrac{147203195}{406224}\)
(-11).36-64.11
= 11.(-36) - 64.11
= 11.(-36 - 64)
= 11.(-100)
= -1100
(-11)*36-64*11
=11*(-36)-64*11
=11*((-36)-64)
=11*(-100)
=-1100
k mik