Rút gọn biểu thức: 3 2 2 + 1 2 4 + 1 2 8 + 1 2 16 + 1
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Những câu hỏi liên quan
5 tháng 11 2017
\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
TP
2
18 tháng 6 2017
3(22 + 1)(24 + 1)(28 + 1)(216 + 1)
=(4 - 1)(22 + 1)(24 + 1)(28 + 1)(216 + 1)
=(22 - 1)(22 + 1)(24 + 1)(28 + 1)(216 + 1)
=(24 - 1)(24 + 1)(28 + 1)(216 + 1)
=(28 - 1)(28 + 1)(216 + 1)
=(216 - 1)(216 + 1)
=(232 - 1)
TN
8 tháng 6 2016
Đặt A=3(22 +1)(24+1)(28+1)(216+1)
=(4-1)(22+1)(24+1)(28+1)(216+1)
=[(22-1)(22+1)](24+1)(28+1)(216+1)
=(24-1)(24+1)(28+1)(216+1)
=(28-1)(28+1)(216+1)
=(216-1)(216+1)
=232-1
8 tháng 6 2016
3(22 +1)(24+1)(28+1)(216+1) = (22 -1)(22 +1)(24+1)(28+1)(216+1) = (24-1)(24+1)(28+1)(216+1) = (28-1)(28+1)(216+1)
= (216-1)(216+1) = 232-1
HA
1
20 tháng 8 2018
Đặt A=3(22 +1)(24+1)(28+1)(216+1)
=(4-1)(2^2+1)(2^4+1)(28+1)(2^16+1)
=[(2^2-1)(2^2+1)](2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)
Theo mình ý a bn làm đc
TN
1
ND
1
M
2 tháng 11 2015
\(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)
\(=\left(6x+1-6x+1\right)^2\)
\(=2^2=4\)
\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
ND
2
22 tháng 8 2015
a) \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)
\(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left(6x-1\right)-2\left(1+6x\right)\left(6x-1\right)\)
\(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left[\left(6x-1\right)-2\left(1+6x\right)\right]\)
\(=\left(6x+1\right)\left(6x+1\right)+\left(6x-1\right)\left(6x-1-2-12x\right)\)
\(=36x^2+12x+1+\left(6x-1\right)\left(-6x-3\right)\)
\(=36x^2+12x+1+\left(-36x^2-12x+3\right)\)
\(=36x^2+12x+1-36x^2-12x+3\)
\(=4\)
3 2 2 + 1 2 2 + 1 2 8 + 1 2 16 + 1 = 2 2 - 1 2 2 + 1 2 4 + 1 2 8 + 1 2 16 + 1 ( v ì 2 2 - 1 = 4 - 1 = 3 ) = 2 4 - 1 2 4 + 1 2 8 + 1 2 16 + 1 = 2 8 - 1 2 8 + 1 2 16 + 1 = 2 16 - 1 2 16 + 1 = 2 32 - 1