Question

[Cao Tùng Lâm]

Tính tỉ số  biết:

Answer 1

[Nguyễn Hoàng Minh]

\(\Rightarrow B=2008+\dfrac{2007}{2}+\dfrac{2006}{3}+...+\dfrac{2}{2007}+\dfrac{1}{2008}\\ \Rightarrow B=\left(\dfrac{2007}{2}+1\right)+\left(\dfrac{2006}{3}+1\right)+...+\left(\dfrac{2}{2007}+1\right)+\left(\dfrac{1}{2008}+1\right)\\ \Rightarrow B=\dfrac{2009}{2}+\dfrac{2009}{3}+...+\dfrac{2009}{2007}+\dfrac{2009}{2008}\\ \Rightarrow B=2009\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2007}+\dfrac{1}{2008}\right)\\ \Rightarrow B=2009\cdot A\\ \Rightarrow\dfrac{A}{B}=\dfrac{1}{2009}\)