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1. FeS+6HNO3------>Fe(NO3)3+ H2SO4+3NO+2H2O
2. FeS2+8HNO3------>Fe(NO3)3+ 2H2SO4+5NO+2H2O
3. 5Zn+ 12HNO3--------->5Zn(NO3)2+N2+6H2O
4. PbO2+4HCl------->PbCl2+Cl2+ 2H2O
5. FeS2+8HNO3------->2H2SO4+ Fe(NO3)2+5NO↑+ 2H2O
6. 2FeI2+ 6H2SO4 đặc, nóng------> Fe2(SO4)3+ 2I2+ 3SO2↑+ 6H2O
Câu 1:
a) 4Al + 3O2 --to--> 2Al2O3
| 2Al0 -6e --> Al2+3 | x2 |
| O20 +4e--> 2O-2 | x3 |
b) 2Fe + 6H2SO4 --> Fe2(SO4)3 + 3SO2 +6 H2O
| 2Fe0-6e-->Fe2+3 | x1 |
| S+6 +2e--> S+4 | x3 |
c) Fe3O4 + 10HNO3 --> 3Fe(NO3)3 + NO2 + 5H2O
| \(Fe_3^{+\dfrac{8}{3}}-1e->3Fe^{+3}\) | x1 |
| \(N^{+5}+1e->N^{+4}\) | x1 |
d) \(10Al+38HNO_3->10Al\left(NO_3\right)_3+2NO+3N_2O+19H_2O\)
\(\dfrac{30.n_{NO}+44.n_{N_2O}}{n_{NO}+n_{N_2O}}=19,2.2=38,4=>\dfrac{n_{NO}}{n_{N_2O}}=\dfrac{2}{3}\)
| Al0 -3e --> Al+3 | x10 |
| 38H+ + 8NO3- +30e--> 2NO + 3N2O + 19H2O | x1 |
e) \(\left(5x-2y\right)M+\left(6nx-2ny\right)HNO_3->\left(5x-2y\right)M\left(NO_3\right)_n+nN_xO_y+\left(3nx-ny\right)H_2O\)
| M0-ne--> M+n | x(5x-2y) |
| \(xN^{+5}+\left(5x-2y\right)e->N_x^{+\dfrac{2y}{x}}\) | xn |
24.
xFe+2y/x --------------> xFe+3 + (3x - 2y)e (x3)
N+ 5 + 3e -------------> N+2 (x(3x-2y))
=> 3xFe+2y/x + (3x-2y)N+5 -----> 3xFe+3 + (3x-2y)N+2
Vậy pư cân bằng như sau:
3FexOy + (12x - 2y)HNO3 ----> 3xFe(NO3)3 + (3x-2y)NO + (6x-y)H2O
25.
xFe+2y/x --------------> xFe+3 + (3x - 2y)e -----------------(x1)
N+ 5 + 1e -------------> N+4 ----------------------- (x(3x-2y))
=> xFe+2y/x + (3x-2y)N+5 -----> xFe+3 + (3x-2y)N+2
Vậy pư cân bằng như sau:
FexOy + (6x - 2y)HNO3 ----> xFe(NO3)3 + (3x-2y)NO2 + (3x-y)H2O
h) 3Cu + 8HNO3 --> 3Cu(NO3)2 + 2NO + 4H2O
| Cu0-2e-->Cu+2 | x3 |
| N+5 +3e--> N+2 | x2 |
i) 4Zn + 10HNO3 --> 4Zn(NO3)2 + N2O + 5H2O
| Zn0-2e-->Zn+2 | x4 |
| 2N+5 +8e--> N2+1 | x1 |
j) 2Al + 6H2SO4 --> Al2(SO4)3 + 3SO2 + 6H2O
| 2Al0-6e-->Al2+3 | x1 |
| S+6 +2e--> S+4 | x3 |
k) 3Fe3O4 + 28HNO3 --> 9Fe(NO3)3 + NO + 14H2O
| \(Fe_3^{+\dfrac{8}{3}}-1e\rightarrow3Fe^{+3}\) | x3 |
| N+5 +3e--> N+2 | x1 |
l) 2KMnO4 + 10FeSO4 + 8H2SO4 --> 2MnSO4 + 5Fe2(SO4)3 + K2SO4 + 8H2O
| Mn+7 +5e--> Mn+2 | x2 |
| 2Fe+2 -2e--> Fe2+3 | x5 |
m) K2Cr2O7 + 14HCl --> 2KCl + 2CrCl3 + 3Cl2 + 7H2O
| Cr+6 +3e--> Cr+3 | x2 |
| 2Cl-1-2e --> Cl20 | x3 |
\(\text{1. 4NH3 + 5O2 → 6H2O + 4NO }\)
\(\text{2 .FeS2 + 8HNO3 → 2H2O + 2H2SO4 + 5NO + Fe(NO3)3}\)
a,8M+10nHNO3-> 8M(NO3)n+ nNH4NO3+ 3H2O
b,2KMnO4 + 10FeSO4 + 8H2SO4 = 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
c, Cu2S.FeS2 + 14HNO3 -----> 2Cu(NO3)2 + Fe(NO3)2 + 8NO + 3H2SO4 + 4H2O
cn phần cuối mk kb
Mk kb có đúng k !!!
Chúc b hk tốt nhá !!!
Đáp án D