K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

28 tháng 6 2020

Bài làm:

\(\frac{3}{200}-\frac{3}{110}-\frac{3}{90}-\frac{3}{72}-\frac{3}{56}-...-\frac{3}{2}\)

\(=\frac{3}{200}-3\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\right)\)

\(=\frac{3}{200}-3\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{10.11}\right)\)

\(=\frac{3}{200}-3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\right)\)

\(=\frac{3}{200}-3\left(1-\frac{1}{11}\right)\)

\(=\frac{3}{200}-\frac{30}{11}=-\frac{5967}{2200}\)

Học tốt!!!!

28 tháng 6 2020

We bear're bears!

:)

20 tháng 2 2019

\(\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+...+\frac{3}{110}\)

\(=3\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{110}\right)\)

\(=3\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{10\cdot11}\right)\)

\(=3\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{10}-\frac{1}{11}\right)\)

\(=3\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=3\cdot\frac{8}{33}=\frac{8}{11}\)

20 tháng 2 2019

https://olm.vn/hoi-dap/detail/63463423750.html

vào tham khảo đi mk nhác trình bày

20 tháng 2 2019

= 3.(1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/110)

= 3.8/33

= 8/11

14 tháng 11 2016

\(\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+\frac{3}{42}+\frac{3}{56}+\frac{3}{72}+\frac{3}{90}+\frac{3}{110}\)

\(=\frac{3}{3\cdot4}+\frac{3}{4\cdot5}+\frac{3}{5\cdot6}+\frac{3}{6\cdot7}+\frac{3}{7\cdot8}+\frac{3}{8\cdot7}+\frac{3}{8\cdot9}+\frac{3}{9\cdot10}+\frac{3}{10\cdot11}\)

\(=3\cdot\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}+\frac{1}{10\cdot11}\right)\)

\(=3\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{10}-\frac{1}{11}\right)\)

\(=3\cdot\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=3\cdot\left(\frac{11}{33}-\frac{3}{33}\right)\)

\(=3\cdot\frac{8}{33}\)

\(=\frac{24}{33}\)

\(=\frac{8}{11}\)

24 tháng 8 2016

ban tra loi dibanh

 

17 tháng 4 2017

\(\frac{3}{5.6}+\frac{3}{6.7}+......+\frac{3}{11.12}=\frac{1}{6}X\)

\(\Rightarrow3.\left(\frac{1}{5.6}+\frac{1}{6.7}+....+\frac{1}{11.12}\right)=\frac{1}{6}X\)

\(\Rightarrow3.\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+.....+\frac{1}{11}-\frac{1}{12}\right)=\frac{1}{6}X\)

\(\Rightarrow3.\left(\frac{1}{5}-\frac{1}{12}\right)=\frac{1}{6}X\)

\(\Rightarrow3.\frac{7}{60}=\frac{1}{6}X\)

\(\Rightarrow\frac{21}{60}=\frac{1}{6}X\)

\(\Rightarrow X=\frac{21}{60}\div\frac{1}{6}=\frac{21}{10}\)

Vậy \(X=\frac{21}{10}\)

8 tháng 7 2023

Bài 1: 

\(101\cdot125+101\cdot25-101\cdot50\)

\(=101\cdot\left(125+25-50\right)\)

\(=101\cdot100\)

\(=10100\)

Bài 2: 

\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)

\(=76\cdot115+24\cdot115\)

\(=115\cdot\left(76+24\right)\)

\(=115\cdot100\)

\(=11500\)

8 tháng 7 2023

còn bài 3,4,5 thì sao ak 

Giải;

1) \(347.222-222.\left(216+184\right):8\) 

\(=347.222-222.400:8\) 

\(=347.222-222.50\) 

\(=222.\left(347-50\right)\) 

\(=222.297\)

\(=65934\) 

2) \(132-\left[116-\left(132-128\right).22\right]\) 

\(=132-\left[116-4.22\right]\) 

\(=132-\left[116-88\right]\) 

\(=132-28\) 

\(=104\) 

3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-175\right]\right\}\) 

\(=16:\left\{400:25\right\}\) 

\(=16:16\) 

\(=1\) 

4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\) 

\(=\left\{184:\left[96-4\right]-2\right\}.3651\) 

\(=\left\{184:92-2\right\}.3651\) 

\(=\left\{2-2\right\}.3651\) 

\(=0.3651\) 

\(=0\) 

5) \(46-\left[\left(16+71.4\right):15\right]-2\) 

\(=46-\left[\left(16+284\right):15\right]-2\) 

\(=46-\left[300:15\right]-2\)

 \(=46-20-2\) 

\(=24\)

6) \(3^3.18+72.4^2-41.18\) 

\(=18.\left(27-41\right)+72.16\) 

\(=18.-14+1152\) 

\(=-252+1152\) 

\(=900\)

Giải: (tiếp)

7) \(\left(56.46-25.23\right):23\) 

\(=\left(2576-575\right):23\) 

\(=2001:23\) 

\(=87\) 

8) \(\left(28.54+56.36\right):21:2\) 

\(=\left(1512+2016\right):21:2\) 

\(=3528:21:2\) 

\(=84\) 

9) \(\left(76.34-19.64\right):\left(38.9\right)\) 

\(=\left(2584-1216\right):342\) 

\(=1368:342\) 

\(=4\) 

10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\) 

\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\) 

\(=\left(2+4+6+...+100\right).0\) 

\(=0\) 

11) \(\left(5.4^{11}-3.16^5\right):4^{10}\) 

\(=5.4^{11}:4^{10}-3.16^5:4^{10}\) 

\(=5.4-3.1\) 

\(=20-3\) 

\(=17\) 

12) \(7256.4375-725:3650+4375.7255\) 

\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\) 

\(=4375.14511-\dfrac{29}{146}\) 

\(=63485624,8\) 

Câu 12 ko chắc!