276:[110-(17-9)^2]-2021^0
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a, - 1,2 + (- 0,8) + 0,25 + 5,75 - 2021
= - (1,2 + 0,8) + (0,25 + 5,75) - 2021
= - 2 + 6 - 2021
= 4 - 2021
= - 2017
b, - 0,1 + \(\dfrac{16}{9}\) + 11,1 - \(\dfrac{20}{9}\)
= (11,1 - 0,1) - (\(\dfrac{20}{9}\) - \(\dfrac{16}{9}\))
= 11 - \(\dfrac{4}{9}\)
= \(\dfrac{95}{5}\)
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\(a,\Leftrightarrow2x\left(x-3\right)\left(x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\\ b,\Leftrightarrow\left(2x-1\right)\left(x-2021\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=2021\end{matrix}\right.\\ c,\Leftrightarrow4x\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\\ d,\Leftrightarrow\left(3x+7-x-1\right)\left(3x+7+x+1\right)=0\\ \Leftrightarrow\left(2x+6\right)\left(4x+8\right)=0\\ \Leftrightarrow\left(x+3\right)\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\end{matrix}\right.\)
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a) \(110 – 7^2 + 22:2\) = \(110 – 49 + 11 = 61 + 11 = 72\)
b) \(9.(8^2 – 15)= 9.(64 – 15 ) = 9.49 = 441\)
c) \(5.8 – (17 + 8):5 = 40 – 25:5 = 40 – 5 = 35\)
d) \( 75:3 + 6.9^2= 25 + 6.81 = 25 + 486 = 511\)
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\(=\dfrac{25}{4}+\dfrac{2}{15}\cdot\dfrac{3}{2}-1+\dfrac{1}{4}=\dfrac{26}{4}-1+\dfrac{1}{5}=\dfrac{22}{4}+\dfrac{1}{5}=\dfrac{114}{20}=\dfrac{57}{10}\)
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a) 17 + 15 + (-27)
= (17 - 27) + 15
= -10 + 15
= 5
b) 13.75 + 25.13 - 300
= 13.(75 + 26) - 300
= 13.100 - 300
= 1300 - 300
= 1000
c) 80 - (4.5² - 5.2³) + 2021⁰
= 80 - (4.25 - 5.8) + 1
= 80 - (100 - 40) + 1
= 80 - 60 + 1
= 20 + 1
= 21
![](https://rs.olm.vn/images/avt/0.png?1311)
= 276 : [ 110 - 82 ] - 1 = 276 : [110 - 64] - 1= 276 : 46 - 1 = 6 - 1 =5
\(276:[110-(17-9)^2]-2021^0\)
\(276:(110-8^2)-1\)
\(276:(110-64)-1\)
\(= \) \(276:46-1\)
\(=\) \(6 -1\)
\(= 5\)