Question

[ʚTrần Hòa Bìnhɞ]

Ai đúng và nhanh 3 tick nha !!!

Bài 5 : Tìm x biết :

a) \(8x\left(x-2017\right)-2x+4034=0\)

b) \(\frac{x}{2}+\frac{x^2}{8}=0\)

c) \(4-x=2\left(x-4\right)^2\)

d) \(\left(x^2+1\right)\left(x-2\right)+2x=4\)

Bài 5 : Rút gọn biểu thức 

a) \(\left(3-xy^2\right)^2-\left(2+xy^2\right)^2\)                             c) \(\left(a-b^2\right)\left(a+b^2\right)\)

b) \(9x^2-\left(3x-4\right)^2\)               d) \(\left(a^2+2a+3\right)\left(a^2+2a-3\right)\)

e) \(\left(x-y+6\right)\left(x+y-6\right)\)    f) \(\left(y+2z-3\right)\left(y-2z-3\right)\)

g) \(\left(2y-5\right)\left(4y^2+10y+25\right)\)    k) \(\left(3y+4\right)\left(9y^2-12y+16\right)\)

i) \(\left(x+3\right)^3+\left(2-x\right)^3\)    j) \(\left(x+y\right)^3-\left(x-y\right)^3\)

Answer 1

[阮草~๖ۣۜDαɾƙ]

a. \(8x\left(x-2017\right)-2x+4034=0\)

\(8x\left(x-2017\right)-2\left(x-2017\right)=0\)

\(\left(8x-2\right)\left(x-2017\right)=0\)

\(\Rightarrow TH1:8x-2=0\)

\(8x=2\)

\(x=\frac{1}{4}\)

\(TH2:x-2017=0\)

\(x=2017\)

Vậy \(x\in\left\{\frac{1}{4};2017\right\}\)

Answer 2

[Nguyễn Văn Tuấn Anh]

Bài 1 

a) \(8x\left(x-2017\right)-2x+4034=0\)

\(\Rightarrow8x\left(x-2017\right)-2\left(x-2017\right)=0\)

\(\Rightarrow\left(x-2017\right)\left(4x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=2017\\x=\frac{1}{4}\end{cases}}\)