\(\frac{8^3.9^5}{6^{15}}\)=?
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PN
1
XO
14 tháng 7 2019
a) \(\frac{9^{10}.27^7}{81^7.3^{15}}\)= \(\frac{\left(3^2\right)^{10}.\left(3^3\right)^7}{\left(3^4\right)^7.3^{15}}\)= \(\frac{3^{2.10}.3^{3.7}}{3^{4.7}.3^{15}}\)=\(\frac{3^{20}.3^{21}}{3^{28}.3^{15}}\)=\(\frac{3^{41}}{3^{43}}\)= \(\frac{3^{41}}{3^{41}.3^2}\)= \(\frac{1}{3^2}=\frac{1}{9}\)
b) \(\frac{8^3.9^5.27^5}{4^5.81^6}\)= \(\frac{\left(2^3\right)^3.\left(3^2\right)^5.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^6}\)= \(\frac{2^{3.3}.3^{2.5}.3^{3.5}}{2^{2.5}.3^{4.6}}\)=\(\frac{2^9.3^{10}.3^{15}}{2^{10}.3^{24}}\)= \(\frac{2^9.3^{25}}{2^{10}.3^{24}}\)=\(\frac{2^9.3^{24}.3}{2^9.2.3^{24}}\)=\(\frac{3}{2}\)
S
14 tháng 10 2019
Trả lời:
\(\frac{32^3.9^5}{8^3.6^6}=\frac{\left(2^5\right)^3.\left(3^2\right)^5}{\left(2^3\right)^3.\left(2.3\right)^6}=\frac{2^{15}.3^{10}}{2^9.2^6.3^6}=\frac{2^{15}.3^{10}}{2^{15}.3^6}=\frac{3^{10}}{3^6}=3^4=81\)
~Std well~
#Mina
14 tháng 10 2019
Trả lời:
\(\frac{32^3.9^5}{8^3.6^6}=\frac{\left(2^5\right)^3.\left(3^2\right)^5}{\left(2^3\right)^3.\left(2.3\right)^6}=2^92^63^6=\frac{2^{15}.3^{10}}{2^{15}.3^6}=\frac{3^{10}}{3^6}=3^4=81\)
#Trúc Mai
ND
1
VM
20 tháng 9 2019
b) \(\frac{2^9.4^{10}}{8^8}=\frac{2^9.\left(2^2\right)^{10}}{\left(2^3\right)^8}=\frac{2^9.2^{20}}{2^{24}}=\frac{2^{29}}{2^{24}}=2^5=32.\)
Chúc bạn học tốt!
15 tháng 12 2019
\(\frac{3^2.6^3.9^6}{2^33^{15}}\)= \(\frac{3^2.2^3.3^3.3^{12}}{2^3.3^{15}}\)= \(\frac{3^{17}}{3^{15}}\)=9
15 tháng 12 2019
32.63.96/23.315= 32.(2.3)3.(32)6/23.315=32.23.33.312/23.315=317.23/23.315= 32 = 9
F
31 tháng 1 2020
Bài giải
\(N=\frac{9\cdot5^{20}\cdot27^9-3\cdot9^{15}\cdot25^9}{7\cdot3^{29}\cdot125^6-3\cdot3^9\cdot15^{19}}=\frac{3^2\cdot5^{20}\cdot\left(3^3\right)^9-3\cdot\left(3^2\right)^{15}\cdot\left(5^2\right)^9}{7\cdot3^{29}\cdot\left(5^3\right)^6-3\cdot3^9\cdot\left(3\cdot5\right)^{19}}=\frac{3^2\cdot5^{20}\cdot3^{27}-3\cdot3^{30}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{10}\cdot3^{19}\cdot5^{19}}\)
\(=\frac{3^{29}\cdot5^{20}-3^{31}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{29}\cdot5^{19}}=\frac{3^{29}\cdot5^{18}\left(5^2-3^2\right)}{3^{29}\cdot5^{18}\left(7-5\right)}=\frac{25-9}{7-5}=\frac{16}{2}=8\)
NN
1
16 tháng 7 2017
1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)
CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E
=\(\frac{1}{15552}\):))))
\(\frac{8^3.9^5}{6^{15}}=\frac{\left(2^3\right)^3.\left(3^2\right)^5}{\left(2.3\right)^{15}}=\frac{2^9.3^{10}}{2^{15}.3^{15}}=\frac{2^9.3^{10}}{2^9.2^6.3^{10}.3^5}=\frac{1}{2^6.3^5}\)