X - 5/6 : 7/6=0,125
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TP
1
23 tháng 10 2021
c: Ta có: \(\left|x+\dfrac{5}{6}\right|:\dfrac{4}{5}=\dfrac{3}{8}\)
\(\Leftrightarrow\left|x+\dfrac{5}{6}\right|=\dfrac{3}{8}\cdot\dfrac{4}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{5}{6}=\dfrac{3}{10}\\x+\dfrac{5}{6}=-\dfrac{3}{10}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-8}{15}\\x=-\dfrac{17}{15}\end{matrix}\right.\)
KQ
5 tháng 3 2023
`a)1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10`
`=(1/10+9/10)+(2/10+8/10)+(3/10+7/10)+(4/10+6/10)+5/10`
`=10/10 + 10/10+10/10+10/10+1/2`
`=1+1+1+1+1/2`
`=2+2+1/2`
`=4+1/2`
`=8/2+1/2`
`=9/2`
__
`13,25:0,5+13,25:0,25+13,25:0,125+13,25×6`
`=13,25×1/(0,5)+13,25×1/(0,25)+13,25×1/(0,125)+13,25×6`
`=13,25×(1/(0,5)+1/(0,25)+1/(0,125)+6)`
`=13,25×(2+4+8+6)`
`=13,25×20`
`=265`
`#QiN`
7 tháng 7 2017
\(x-\frac{5}{6}:1\frac{1}{6}=0,125\)
\(x-\frac{5}{6}:\frac{7}{6}=0,125\)
\(x-\frac{5}{7}=0,125\)
\(x=0,125+\frac{5}{7}\)
\(x=\frac{47}{56}\)
22 tháng 5 2018
\(x-\frac{5}{6}\div\frac{1}{\frac{1}{3}}=0,125\)
\(x-\frac{5}{6}\div3=\frac{1}{8}\)
\(x-\frac{5}{18}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{18}\)
\(x=\frac{29}{72}\)
QN
22 tháng 5 2018
\(x-\frac{5}{6}:\frac{1}{\frac{1}{3}}=0,125\)
\(x-\frac{5}{6}:\frac{1}{\frac{1}{3}}=\frac{1}{8}\)
\(x-\frac{5}{6}:3=\frac{1}{8}\)
\(x-\frac{5}{18}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{18}\)
\(x=\frac{29}{72}\)
Vậy x = \(\frac{29}{72}\)
DQ
2
23 tháng 5 2018
\(x-\frac{5}{6}:1\frac{1}{6}=0.125\)
\(x-\frac{5}{6}:\frac{7}{6}=\frac{1}{8}\)
\(x-\frac{5}{6}\cdot\frac{6}{7}=\frac{1}{8}\)
\(x-\frac{5}{7}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{7}\)
\(x=\frac{47}{56}\)
23 tháng 5 2018
x - 5/6 : 1 1/6 = 0,125
\(\Rightarrow\)x - 5/6 : 7/6 = 1/8
\(\Rightarrow\)x - 5/7 = 1/8
\(\Rightarrow\)x = 1/8 + 5/7 = 47/56
vậy x = 47/56
HB
2
31 tháng 10 2021
a, \(\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}:\left(-\dfrac{3}{2}\right)=\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}.\left(-\dfrac{2}{3}\right)==\dfrac{3}{5}\left(-\dfrac{8}{3}-\dfrac{2}{3}\right)=\dfrac{3}{5}.\left(-\dfrac{10}{3}\right)=-2\)
b, \(-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)-\left(-\dfrac{21}{15}\right)=-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)+\dfrac{7}{5}=\dfrac{10}{7}+\dfrac{7}{5}=\dfrac{50+49}{35}=\dfrac{99}{35}\)
31 tháng 10 2021
a: \(=\dfrac{3}{5}\cdot\left(-\dfrac{8}{3}+\dfrac{-2}{3}\right)=\dfrac{3}{5}\cdot\dfrac{-10}{3}=-2\)
c: \(=\left(0.125\right)^{650}\cdot8^{102}\)
\(=\left(0.125\cdot8\right)^{102}\cdot\left(0.125\right)^{548}\)
\(=\dfrac{1}{8^{548}}\)
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\(x-\frac{5}{6}\text{ : }\frac{7}{6}=0,125\)
\(x-\frac{5}{6}\cdot\frac{6}{7}=0,125\)
\(x-\frac{5}{7}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{7}\)
\(x=\frac{47}{56}\)