Tìm x
X-2=3
(6 và 3/7-0,75x-2/0,35)×2,8=10
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ZT
1
17 tháng 9 2016
\(\Leftrightarrow\left(\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right).2,8+1,75\right)=0,1175\)
\(\Leftrightarrow\left(\frac{45}{7}-\frac{0,75x-2}{0,35}\right).2,8=-1,6325\)
\(\Leftrightarrow\frac{45}{7}-\frac{0,75x-2}{0,35}=\frac{-653}{1120}\)
\(\Leftrightarrow\frac{0,75x-2}{0,35}=\frac{7853}{1120}\Leftrightarrow x=5,93875\)
DH
27 tháng 7 2020
\(\left[\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8+1,75\right]:0,05=235\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8+1,75=11,75\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8=10\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8=10\)
\(\Leftrightarrow6\frac{3}{7}-\frac{0,75x-2}{0,35}=\frac{25}{7}\)
\(\Leftrightarrow\frac{0,75x-2}{0,35}=\frac{20}{7}\)
\(\Leftrightarrow0,75x-2=1\)
\(\Leftrightarrow0,75x=3\)
\(\Leftrightarrow x=4\)
Vậy \(x=4\)
21 tháng 5 2022
a: Sửa đề: \(\left[\left(6\dfrac{3}{7}-\dfrac{0,75x-2}{0,35}\right)\cdot2.8+1.75\right]\cdot0.05=2.35\)
\(\Leftrightarrow\left(\dfrac{45}{7}-\dfrac{15x-40}{7}\right)\cdot2.8+1,75=47\)
\(\Leftrightarrow\dfrac{45-15x+40}{7}\cdot2,8=45,25\)
\(\Leftrightarrow\dfrac{85-15x}{7}=\dfrac{905}{56}\)
=>8(85-15x)=905
=>680-120x=905
=>120x=-225
hay x=-15/8
b: \(\dfrac{3}{5}-\dfrac{2}{7}< \dfrac{2}{3}x+\dfrac{3}{4}< \dfrac{1}{2}+\dfrac{7}{9}\)
\(\Leftrightarrow\dfrac{11}{35}-\dfrac{3}{4}< \dfrac{2}{3}x< \dfrac{23}{18}-\dfrac{3}{4}\)
\(\Leftrightarrow-\dfrac{61}{140}< \dfrac{2}{3}x< \dfrac{19}{36}\)
\(\Leftrightarrow-\dfrac{183}{280}< x< \dfrac{19}{24}\)
29 tháng 10 2021
3: \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
\(\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)
x - 2 =3
x =3+2
x =5
\(6\frac{3}{7}-0,75x-\frac{2}{0,35}\times2,8=10\)
\(\frac{45}{7}-\frac{3}{4}x-\frac{40}{7}\times\frac{28}{10}=10\)
\(\frac{45}{7}-\frac{3}{4}x=10+4\)
\(\frac{3}{4}x=\frac{45}{7}-14\)
\(\frac{3}{4}x=-\frac{53}{7}\)
\(x=-\frac{53}{7}:\frac{3}{4}\)
\(x=\frac{-212}{21}\)