1/2.(x-2/3)-20%(3x-1,5)=0,4
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NT
2
TQ
27 tháng 1 2018
<=>\(\dfrac{\left(3x-0,4\right)15}{30}+\dfrac{\left(1,5-2x\right)10}{30}=\dfrac{\left(x+0,5\right)6}{30}\)
=>\(\left(3x-0,4\right)15+\left(1,5-2x\right)10=\left(x+0,5\right)6\)
<=>\(45x-6+15-20x=6x+3\)
<=>\(45x-20x-6x=6+3-15\)
<=>\(19x=-6\)
<=>\(x=\dfrac{-6}{19}\)
24 tháng 6 2019
ko ghi lại đề TL:
a,\(\frac{6x+30}{12}+\frac{9-6x}{12}=\frac{12x}{12}-\frac{14+2x}{12}\)
6x+30+9-6x=12x-14-2x
39=10x-14
10x=39+14=53
x=5,3
vậy.........
câu B ,c làm tương tự
học tốt
16 tháng 2 2019
\(\frac{x}{0,5}+\frac{x}{0,25}+\frac{x}{0,2}=5,5\)
\(\Rightarrow x\cdot2+x\cdot4+x\cdot5=5,5\)
\(\Rightarrow x\cdot(2+4+5)=5,5\)
\(\Rightarrow x\cdot11=5,5\)
\(\Rightarrow x=5,5\div11=0,5\)
16 tháng 2 2019
\(20\%x+0,4x=12\)
\(\Rightarrow0,2x+0,4x=12\)
\(\Rightarrow(0,2+0,4)x=12\)
\(\Rightarrow0,6x=12\)
\(\Rightarrow x=20\)
TN
24 tháng 6 2018
\(\left(0,4x-2\right)-\left(1,5x+1\right)\) \(\left(-4x-0,8\right)\)\(=3,6\)
<=>\(\left(0,4x-2\right)-\)\(\left(-6x^2-1,2x-4x-0,8\right)\)\(=3,6\)
<=> \(0,4x-2+6x^2+1,2x\)\(+4x+0,8=3,6\)
<=> \(6x^2+5,6x-1,2=3,6\)
<=> \(6x^2+5,6x-4,8=0\)
<=>
18 tháng 5 2021
a) Ta có: \(6x\left(x-5\right)+3x\left(7-2x\right)=18\)
\(\Leftrightarrow6x^2-30x+21x-6x^2=18\)
\(\Leftrightarrow-9x=18\)
hay x=-2
Vậy: S={-2}
b) Ta có: \(2x\left(3x+1\right)+\left(4-2x\right)\cdot3x=7\)
\(\Leftrightarrow6x^2+2x+12x-6x^2=7\)
\(\Leftrightarrow14x=7\)
hay \(x=\dfrac{1}{2}\)
Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)
c) Ta có: \(0.5x\left(0.4-4x\right)+\left(2x+5\right)\cdot x=-6.5\)
\(\Leftrightarrow0.2x-2x^2+2x^2+5x=-6.5\)
\(\Leftrightarrow5.2x=-6.5\)
hay \(x=-\dfrac{5}{4}\)
Vậy: \(S=\left\{-\dfrac{5}{4}\right\}\)
18 tháng 5 2021
d) Ta có: \(\left(x+3\right)\left(x+2\right)-\left(x-2\right)\left(x+5\right)=6\)
\(\Leftrightarrow x^2+5x+6-\left(x^2+3x-10\right)=6\)
\(\Leftrightarrow x^2+5x+6-x^2-3x+10=6\)
\(\Leftrightarrow2x+16=6\)
\(\Leftrightarrow2x=-10\)
hay x=-5
Vậy: S={-5}
e) Ta có: \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)
\(\Leftrightarrow3\left(6x^2-5x+1\right)-\left(18x^2-29x+3\right)=0\)
\(\Leftrightarrow18x^2-15x+3-18x^2+29x-3=0\)
\(\Leftrightarrow14x=0\)
hay x=0
Vậy: S={0}
3 tháng 5 2020
a) Ta có: \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\)
\(\Leftrightarrow\frac{63\left(3x-11\right)}{693}-\frac{231x}{693}-\frac{99\left(3x-5\right)}{693}+\frac{77\left(5x-3\right)}{693}=0\)
\(\Leftrightarrow189x-693-231x-297x+495+385x-231=0\)
\(\Leftrightarrow46x-429=0\)
\(\Leftrightarrow46x=429\)
hay \(x=\frac{429}{46}\)
Vậy: \(x=\frac{429}{46}\)
b) Ta có: \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{5}\)
\(\Leftrightarrow\frac{9x-0,7}{4}-\frac{5x-1,5}{7}-\frac{7x-1,1}{6}+\frac{5\left(0,4-2x\right)}{5}=0\)
\(\Leftrightarrow105\left(9x-0,7\right)-60\left(5x-1,5\right)-70\left(7x-1,1\right)+420\left(0,4-2x\right)=0\)
\(\Leftrightarrow945x-\frac{147}{2}-300x+90-490x+77+168-840x=0\)
\(\Leftrightarrow-685x+261.5=0\)
\(\Leftrightarrow-685x=-261.5\)
hay \(x=\frac{523}{1370}\)
Vậy: \(x=\frac{523}{1370}\)
c) Ta có: \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x-1\right)}{7}-5\)
\(\Leftrightarrow\frac{14\left(5x-3\right)}{84}-\frac{21\left(7x-1\right)}{84}-\frac{24\left(2x-1\right)}{84}+\frac{420}{84}=0\)
\(\Leftrightarrow70x-42-147x+21-48x+24+420=0\)
\(\Leftrightarrow-125x+423=0\)
\(\Leftrightarrow-125x=-423\)
hay \(x=\frac{423}{125}\)
Vậy: \(x=\frac{423}{125}\)
d) Ta có: \(14\frac{1}{2}-\frac{2\left(x+3\right)}{5}=\frac{3x}{2}-\frac{2\left(x-7\right)}{3}\)
\(\Leftrightarrow\frac{435}{30}-\frac{12\left(x+3\right)}{30}-\frac{45x}{30}+\frac{20\left(x-7\right)}{30}=0\)
\(\Leftrightarrow435-12x-36-45x+20x-140=0\)
\(\Leftrightarrow-37x+259=0\)
\(\Leftrightarrow-37x=-259\)
hay \(x=7\)
Vậy: x=7
2 tháng 1 2018
\(a,\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
\(\Leftrightarrow\dfrac{15x-6-8}{4}=\dfrac{7x-15\left(x-7\right)}{3}\)
\(\Leftrightarrow\dfrac{15x-14}{4}=\dfrac{7x-15x+105}{3}\)
\(\Leftrightarrow\dfrac{45x-42}{12}=\dfrac{-32x+420}{12}\)
\(\Leftrightarrow45x+32x=420+42\)
\(\Leftrightarrow77x=462\)
\(\Leftrightarrow x=6\)
\(b,\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
\(\Leftrightarrow\dfrac{2x+10+3-2x}{4}=\dfrac{6x-7-x}{6}\)
\(\Leftrightarrow\dfrac{13}{4}=\dfrac{5x-7}{6}\)
\(\Leftrightarrow2\left(5x-7\right)=3.13\)
\(\Leftrightarrow10x-14=39\)
\(\Leftrightarrow10x=53\)
\(\Leftrightarrow x=5,3\)
\(c,\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
\(\Leftrightarrow\dfrac{3x-9+11x+11}{33}=\dfrac{x+7-9}{9}\)
\(\Leftrightarrow\dfrac{14x+2}{33}=\dfrac{x-2}{9}\)
\(\Leftrightarrow33\left(x-2\right)=9\left(14x+2\right)\)
\(\Leftrightarrow33x-66=126x+18\)
\(\Leftrightarrow-93x=84\)
\(\Leftrightarrow x=-\dfrac{28}{31}\)
\(d,\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
\(\Leftrightarrow\dfrac{3\left(3x-0,4\right)+2\left(1,5-2x\right)}{6}=\dfrac{x+0,5}{5}\)
\(\Leftrightarrow\dfrac{9x-1,2+3-4x}{6}=\dfrac{x+0,5}{5}\)
\(\Leftrightarrow\dfrac{5x+1,8}{6}=\dfrac{x+0,5}{5}\)
\(\Leftrightarrow5\left(5x+1,8\right)=6\left(x+0,5\right)\)
\(\Leftrightarrow25x+9=6x+3\)
\(\Leftrightarrow19x=-6\)
\(\Leftrightarrow x=-\dfrac{6}{19}\)
\(\Leftrightarrow77x=378\)
\(\Leftrightarrow x=\dfrac{54}{11}\)
\(\frac{1}{2}.\left(x-\frac{2}{3}\right)-20\%.\left(3x-1,5\right)=0,4\)
\(\Rightarrow\frac{1}{2}.\left(x-\frac{2}{3}\right)-\frac{1}{5}.\left(3x-\frac{3}{2}\right)=\frac{2}{5}\)
\(\Rightarrow\frac{1}{2}.x-\frac{1}{3}-\frac{3}{5}x-\frac{3}{10}=\frac{2}{5}\)
\(\Rightarrow\left(\frac{1}{2}-\frac{3}{5}\right).x=\frac{2}{5}+\frac{3}{10}+\frac{1}{3}\)
\(\Rightarrow\frac{-1}{10}.x=\frac{31}{30}\)
\(\Rightarrow x=\frac{31}{30}:\frac{-1}{10}\)
\(\Rightarrow x=-\frac{31}{3}\)
P/s : Tính theo cách này đúng nhưng sao mk thử lại sai, có j sai trong câu trl mong cacau giúp đỡ :v
\(\frac{1}{2}\left[x-\frac{2}{3}\right]-20\%\left[3x-\frac{1}{5}\right]=0,4\)
\(\Rightarrow\frac{1}{2}x-\frac{1}{3}-\frac{20}{100}\left[3x-\frac{1}{5}\right]=0,4\)
\(\Rightarrow\frac{1}{2}x-\frac{1}{3}-\frac{1}{5}\left[3x-\frac{1}{5}\right]=0,4\)
\(\Rightarrow\frac{1}{2}x-\frac{1}{3}-\frac{3x}{5}-\frac{1}{25}=0,4\)
Làm nốt :v