tìm x biết 3/2.4^x+5/3.4^x 2=3/2.4^8+5/3.4^10
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1, \(3\left(x+5\right)=3x+3.5=3x+15\)
2, \(5\left(2+x\right)=5.2+5x=10+5x\)
3, \(4\left(x-2\right)=4x-4.2=4x-8\)
4, \(2x+2.5=2\left(x+5\right)\)
5, \(3.4+4x=4\left(x+3\right)\)
6, \(2x-2.4=2\left(x-4\right)\)
Chúc học tốt
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\(M=\dfrac{2^2.3^2.4^2.....20^2}{1.3.2.4.3.5.4.6.5.7.6.8.7.9....19.21}=\)
\(=\dfrac{2^2.3^2.4^2....20^2}{1.2.3^2.4^2....19^2.20.21}=\dfrac{2.20}{21}=\dfrac{40}{21}\)
\(N=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.....\dfrac{10}{11}=\dfrac{1}{11}\)
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Sử dụng tính chất phân phối để điền vào chỗ trống
3(x +) =....( viết thiếu )
(2+x)5=2.5+ x.5
3.4+4x = (3+x).4
2x + 2.5 =2.(x+5)
4(x-2) =4.x-4.2
2x-2.4 =2.(x-4)
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a, Ta có : \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{199}-\frac{1}{200}\)
\(=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{199}+\frac{1}{200}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{199}+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
=> \(\frac{\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{199.200}}{\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}}=1\)
=> đpcm
Study well ! >_<
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a. 20 + 8.(x + 3) = 52 . 4
8.(x + 3) = 100 - 20
x + 3 = 80 : 8
x = 10 - 3
x = 7
b. 120 + |x| = 150
|x| = 150 - 120
|x| = 30
x = + 30
a) 20 + 8(x + 3) = 52 . 4
20 + 8(x + 3) = 100
8(X + 3) = 100 - 20
8(x + 3) = 80
x + 3 = 80 : 8
x + 3 = 10
x = 10 - 3
x = 7
b) 120 + |x| = 150
|x| = 150 - 120
|x| = 30
=> \(\orbr{\begin{cases}x=30\\x=-30\end{cases}}\)
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\(2.4:\left(\frac{-1}{2}-x\right)=\frac{8}{5}\)
\(8:\left(\frac{-1}{2}-x\right)=\frac{8}{5}\)
\(\frac{-1}{2}-x=5\)
\(x=\frac{-55}{10}\)
Vậy \(x=\frac{-55}{10}\)
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1/3+1/15+1/35+1/63+1/99+1/143+1/195
=1/1*3+1/3*5+1/5*7+1/7*9+1/9*11+1/11*13+1/13*15
suy ra 2(1/1*3+1/3*5+1/5*7+1/7*9+1/9*11+1/11*13+1/13*15)
=2/1*3+2/3*5+2/5*7+2/7*9+2/9*11+2/11*13+2/13*15
=1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13+1/13-1/15
=1-1/15
=14/15
a=14/15 chia 2=7/15
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1) (-10)-|5-x|=(-12)
|5-x|=(-10)-(-12)
|5-x|=2
\(\Rightarrow\left[{}\begin{matrix}5-x=2\\5-x=\left(-2\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=7\end{matrix}\right.\)
Vậy:............