Question

[Le Thu Trang]

a) [\(2^{-2}\) + 0,75] . \(3\dfrac{3}{5}\) - \(\sqrt{\dfrac{36}{25}}\) : \(\left(-1\dfrac{4}{5}\right)\) + 4 . \(\left(-\dfrac{1}{2015}\right)^0\)

b) \(\left(-\dfrac{3}{5}\right)^2\) . \(\left(0,6-\left|\dfrac{1}{2}-\dfrac{1}{5}\right|\right)\) - \(\sqrt{\left(\dfrac{-3}{8}\right)^2}\) : \(1\dfrac{1}{8}\)

c) \(\sqrt{0,49}\) : \(\sqrt{\dfrac{16}{25}}\) + \(\sqrt{\dfrac{4}{81}}\) : \(\sqrt{\dfrac{25}{81}}\) - \(\left(-\dfrac{1}{2}\right)^3\)

d) \(19\dfrac{1}{3}\) : \(\dfrac{7}{3}\) - \(33\dfrac{1}{3}\) : \(\dfrac{7}{3}\) - \(\left|-\dfrac{2}{7}\right|\)

e) \(\dfrac{4^6.9^5+6^9.120}{-6^{11}-8^4.3^{12}}\)

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Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\cdot\dfrac{18}{5}-\dfrac{6}{5}:\dfrac{-9}{5}+4\)

\(=\dfrac{18}{5}-\dfrac{6}{5}\cdot\dfrac{-5}{9}+4\)

\(=\dfrac{18}{5}+\dfrac{2}{3}+4\)

\(=\dfrac{124}{15}\)

b: \(=\dfrac{9}{25}\cdot\left(\dfrac{3}{5}-\dfrac{1}{5}+\dfrac{1}{2}\right)-\dfrac{3}{8}:\dfrac{9}{8}\)

\(=\dfrac{9}{25}\cdot\dfrac{4}{10}-\dfrac{1}{3}\)

\(=-\dfrac{71}{375}\)

c: \(=\dfrac{7}{10}:\dfrac{4}{5}+\dfrac{2}{9}:\dfrac{5}{9}+\dfrac{1}{8}\)

\(=\dfrac{7}{10}\cdot\dfrac{5}{4}+\dfrac{2}{5}+\dfrac{1}{8}\)

=1+2/5

=7/5

d: \(=\dfrac{3}{7}\left(19+\dfrac{1}{3}-33-\dfrac{1}{3}\right)-\dfrac{2}{7}=\dfrac{3}{7}\cdot\left(-14\right)-\dfrac{2}{7}=-6-\dfrac{2}{7}=\dfrac{-44}{7}\)

e: \(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{-2^{11}\cdot3^{11}-2^{12}\cdot3^{12}}\)

\(=\dfrac{2^{12}\cdot3^{10}\cdot6}{-2^{11}\cdot3^{11}\left(1+2\cdot3\right)}=-\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot7}=\dfrac{-4}{7}\)