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25 tháng 8 2017

\(\frac{2011.2010-1}{2009.2011+2010}=\frac{2011.\left(2009+1\right)-1}{2009.2011+2010}\)

\(=\frac{2011.2009+2011-1}{2009.2011+2010}\)

\(=\frac{2011.2009+2010}{2009.2011+2010}\)

\(=1\)

Nhớ k vs kp với mik nhé,mấy man!

28 tháng 7 2018

đổi k ko

30 tháng 3 2017

=1 nha ban

30 tháng 3 2017

\(=\frac{2008+2009.2010}{2010.\left(2009+2\right)-2012}\)

\(=\frac{2009.2010+2008}{2010.2009+2010.2-2012}\)

\(=\frac{2008+2009.2010}{2008+2009.2010}=1\)

18 tháng 5 2022

\(=\dfrac{2019.2010+1,005.2010}{2011.2010+2.2010}=\dfrac{2010\left(2019+1,005\right)}{2010\cdot\left(2011+2\right)}\)

\(=\dfrac{2020,005}{2013}=\dfrac{2020005}{2013000}=\dfrac{404001}{402600}\)

28 tháng 4 2017

2/1*2*3+2/3*4*5+...+2/2009*2010*2011

A=2/2*(1/1-1/2-1/3+1/2-1/3-1/4+1/4-1/5-1/6+...+1/2009-1/2010-1/2011

A=1*(1-1/2011)

A=1*2010/2011=2010/2011

suy ra: 2010/2011<1 

suy ra 1/2 của 1 lớn hơn 2010/2011

VẬY A NHỎ HƠN 1/2

VẬY 

29 tháng 3 2016

= 2009 * ( 2011 - 1 ) - 1000 / 2011 * 2009 - 1009                                         

= 2009 * 2011 - 2009 -1000 / 2011 * 2009 - 1009                                                                                              

= 2009 * 2011 - 1009 / 2011 * 2009 - 1009                                                                                                      

= 1 

28 tháng 9 2020

\(\frac{2011\cdot2010-1}{2009\cdot2011+2010}=\frac{2011\cdot\left(2009+1\right)-1}{2009\cdot2011+2010}=\frac{2011\cdot2009+2011\cdot1-1}{2009\cdot2011+2010}=\frac{ }{ }\)\(\frac{2011\cdot2009+2011-1}{2009\cdot2011+2010}=\frac{2011\cdot2009+2010}{2009\cdot2011+2010}=1\)

30 tháng 5 2018

\(\frac{2010\cdot2011+1000}{2012\cdot2010-1010}\)

\(\frac{2010\cdot2011+1000}{\left(2011+1\right)\cdot2010-1010}\)

\(\frac{2010\cdot2011+1000}{2011\cdot2010+2010-1010}\)

\(\frac{2010\cdot2011+1000}{2011\cdot2010+1000}\)

= 1

30 tháng 5 2018

\(\frac{2010.2011+1000}{2012.2010-1010}\)

\(=\frac{2010.2011+2010-1010}{2012.2010-1010}\)

\(=\frac{2010.\left(2011+1\right)-1010}{2012.2010-1010}\)

\(=\frac{2010.2012-1010}{2012.2010-1010}\)

\(=1\)

31 tháng 7 2020

\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)

\(\Leftrightarrow2x-4,36=1\)

\(\Leftrightarrow2x=5,36\)

\(\Leftrightarrow x=2,68\)

b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)

Bài 1:

a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)

\(\frac{2\cdot x-4,36}{0,125}=8\)

\(2\cdot x-4,36=8\cdot0,125\)

\(2\cdot x-4,36=1\)

\(2\cdot x=1+4,36\)

\(2\cdot x=5,36\)

\(x=\frac{5,36}{2}=2,68\)

b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)

\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)

\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)

\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)

\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)

Bài 2:

a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )

\(x+5,2=4,7\cdot3,2+0,5\)

\(x+5,2=15,54\)

\(x=15,54-5,2=10,34\)

b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)

Bài 3:

a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)

\(x\cdot\left(104,5-14,1+9,6\right)=25\)

\(x\cdot100=25\)

\(x=\frac{25}{100}=\frac{1}{4}=0,25\)

b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)