bn nào thong minh giải hộ tui với : 35-(7-x)^3=8
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,-\frac{9}{12}=-\frac{9:3}{12:3}=-\frac{3}{4}\)
\(\frac{-18}{-24}=\frac{\left(-18\right):\left(-6\right)}{\left(-24\right):\left(-6\right)}=\frac{3}{4}\)
\(-\frac{35}{70}=-\frac{35:35}{70:35}=\frac{1}{2}\)
\(-\frac{9}{27}=-\frac{9:9}{27:9}=-\frac{1}{3}\)
\(b,\frac{1313}{4242}=\frac{1313:101}{4242:101}=\frac{13}{42}\)
\(\frac{-353535}{-424242}=\frac{\left(-353535\right):\left(-70707\right)}{\left(-424242\right):\left(-70707\right)}=\frac{5}{6}\)
\(c,\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}=\frac{2^3\times4^3\times25^2}{8\times8^2\times25^2\times25\times7}\) ( 4^3 = 8^2 ; 5^4 = 25^2 )
\(=\frac{1}{25\times7}=\frac{1}{175}\)
\(a.\frac{-9}{-12}=\frac{-9:3}{-12:3}=\frac{-3}{-4}.\)
\(\frac{-18}{-24}=\frac{-18:6}{-24:6}=\frac{-3}{-4}\)
\(\frac{-35}{-70}=\frac{-35:35}{-70:35}=\frac{-1}{-2}\)
\(\frac{-9}{-27}=\frac{-9:9}{-27:9}=\frac{-1}{-3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)5/12 - 15/8 : 9 = 5/12 - 5/24 = 10/24 -5/24 = 5/24
b)35/13 - 2 + 6 x 7/6 = 35/13 - 2 + 7 = 100/13
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời:
(-65)-(-37)
= (-65)+37
=-28
(-159)-280:(-7)
=(-159)-(-40)
=(-159)+40
=-119
(-12).\(3^2\)+240:\(\left(-2\right)^2\)
=-108+60
=-48
\(5.\left(-2\right)^3-36:3^2\)
=\(-40-4\)
=\(-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]:\left(-4\right)\)
=\(128-\left[68+8.4\right]:\left(-4\right)\)
=\(128-\left[68+32\right]:\left(-4\right)\)
=\(128-100:\left(-4\right)\)
=\(128-\left(-25\right)\)
=\(153\)
\(-141+3^3+\left(-2\right)^2\)
=\(-141+9+4\)
=\(-132+4\)
=\(-128\)
chúc bạN HOK TỐT
1)(-65)-(-37)=-28
2)(-159)-280:(-7)
=(-159)-(-40)
=-119
3)(-12).3\(^2\)+240:(-2)\(^{^2}\)
=-108+60
=-48
4)5.(-2)\(^3\)-36:3\(^2\)
=-40-4
=-44
5) 128-[68+8.(35-37)2]:(-4)
=128-[68+8.-2\(^2\)]:(-4)
=128-[68+32]:(-4)
=128-100:(-4)
=128-(-25)
=153
6)-141+3\(^3\)+(-2)\(^2\)
=-114+4
=-110
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(-65\right)-\left(-37\right)=\left(-65\right)+37=-\left(65-37\right)=-28\)
\(\left(-159\right)-280\div\left(-7\right)=\left(-159\right)-\left(-40\right)=-119\)
\(\left(-12\right).3^2+240\div\left(-2\right)^2=\left(-12\right).9+240\div4=\left(-108\right)+60=-48\)
\(5.\left(-2\right)^3-36\div3^2=5.\left(-8\right)-36\div9=\left(-40\right)-4=-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]\div\left(-4\right)=128-\left[69+8\left(-2\right)^2\right]\div4\)
\(=128-\left(69+8.4\right)\div4=128-101\div4=128-25,25=102,75\)
\(\left(-141\right)+3^3+\left(-2\right)^2=\left(-141\right)+27+4=\left(-141\right)+31=-110\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(x\left(x+1\right)\left(x+2\right)\left(x+3\right)=8\)
\(\Leftrightarrow\left[x\left(x+3\right)\right].\left[\left(x+1\right)\left(x+2\right)\right]=8\)
\(\Leftrightarrow\left(x^2+3x\right)\left(x^2+3x+2\right)=8\)
Đặt \(t=x^2+3x+1\) thì
\(\left(t-1\right)\left(t+1\right)=8\)
\(\Leftrightarrow t^2-9=0\)
\(\Leftrightarrow\left[{}\begin{matrix}t=3\\t=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+3x+1=3\\x^2+3x+1=-3\end{matrix}\right.\)
Đến đây dễ rồi
b) \(\left(x^2+x\right)\left(x^2+x-2\right)=3\)
Đặt \(t=x^2+x-1\) thì
\(\left(t+1\right)\left(t-1\right)=3\)
\(\Leftrightarrow t^2-4=0\)
\(\Leftrightarrow\left[{}\begin{matrix}t=2\\t=-2\end{matrix}\right.\)
Tương tự bài trên nha
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x=24/35 -2/7
x=14/35
b) x=7/8+5/6
x=41/24
c) x-11/5=3/5
x=11/5+3/5
x=14/5
tick cho mình nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{10}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)
\(=\left(\frac{10}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)
\(=\frac{2}{3}\left(\frac{10}{7}-\frac{3}{7}\right)+\frac{5\cdot10}{6\cdot3}\)
\(=\frac{2}{3}\cdot1+\frac{25}{9}\)
\(=\frac{2}{3}+\frac{25}{9}\)
\(=\frac{31}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)
\(=\left(\frac{1}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)
\(=\frac{2}{3}\cdot\left(-\frac{2}{7}\right)+\frac{5}{3}\cdot\frac{5}{3}\)
\(=-\frac{4}{21}+\frac{25}{6}=\frac{167}{42}\)
Xin lỗi không nhanh được
\(35-\left(7-x\right)^3=8\)
\(\Rightarrow\left(7-x\right)^3=35-8\)
\(\Rightarrow\left(7-x\right)^3=27\)
\(\Rightarrow\left(7-x\right)^3=3^3\)
\(\Rightarrow7-x=3\)
\(\Rightarrow x=7-3\)
\(\Rightarrow x=4\)