(27/25-4/9)-(2/25-5/9)
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2/25=.2../25 .27../36=3/4
3/.12..=9/36
15/27=5/..9..
..20..28=5/7
36/72=..1../2
\(\dfrac{2}{25}=\dfrac{2}{25}\)
\(\dfrac{27}{36}=\dfrac{3}{4}\)
\(\dfrac{3}{12}=\dfrac{9}{36}\)
\(\dfrac{15}{27}=\dfrac{5}{9}\)
\(\dfrac{20}{28}=\dfrac{5}{7}\)
\(\dfrac{36}{72}=\dfrac{1}{2}\)
\(\frac{21}{11}\cdot\frac{68}{63}\cdot\frac{22}{17}\)
\(=1\cdot\frac{4}{3}\cdot2\)
\(=\frac{8}{3}\)
\(\left(\frac{27}{25}-\frac{4}{9}\right)-\left(\frac{2}{25}+\frac{5}{9}\right)\)
\(=\frac{27}{25}-\frac{4}{9}-\frac{2}{25}-\frac{5}{9}\)
\(=\left(\frac{27}{25}-\frac{2}{25}\right)-\left(\frac{4}{9}+\frac{5}{9}\right)\)
\(=1-1\)
\(=0\)
\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}\left(\frac{27}{4}-\frac{22}{25}\right)\)
\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}.\left(\frac{27}{4}-\frac{22}{25}\right)=\frac{22}{25}.\frac{5}{11}-\frac{22}{25}.\frac{8}{9}-\frac{8}{9}.\frac{27}{4}+\frac{8}{9}.\frac{22}{25}=\frac{2}{5}-\frac{6}{1}=\frac{-28}{5}\)
`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
\(\frac{21}{11}\times\frac{22}{17}\times\frac{68}{63}\)
=\(\frac{21}{1}\times\frac{2}{17}\times\frac{68}{63}\)
= 21 x \(\frac{8}{63}\)
=\(\frac{8}{3}\)
B = \(\dfrac{25}{18}\) - \(\dfrac{5}{4}\) : \(\dfrac{3}{2}\) + \(\dfrac{9}{4}\) \(\times\) \(\dfrac{16}{27}\)
B = \(\dfrac{25}{18}\) - \(\dfrac{5}{4}\) \(\times\) \(\dfrac{2}{3}\) + \(\dfrac{4}{3}\)
B = \(\dfrac{25}{18}\) - \(\dfrac{5}{6}\) + \(\dfrac{4}{3}\)
B = \(\dfrac{25}{18}\) - \(\dfrac{15}{18}\) + \(\dfrac{24}{18}\)
B = \(\dfrac{34}{18}\)
B = \(\dfrac{17}{9}\)
\(\left(\frac{27}{25}-\frac{4}{9}\right)-\left(\frac{2}{25}-\frac{5}{9}\right)\)
\(=\frac{27}{25}-\frac{4}{9}-\frac{2}{25}+\frac{5}{9}\)
\(=\left(\frac{27}{25}-\frac{2}{25}\right)+\left(-\frac{4}{9}+\frac{5}{9}\right)\)
\(=\frac{25}{25}+\frac{1}{9}=1+\frac{1}{9}=\frac{9}{9}+\frac{1}{9}\)
\(=\frac{10}{9}\)