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4 tháng 9 2018

Câu a : Ta có :

\(B=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^8-1\right)\left(2^8+1\right)\)

\(=2^{16}-1< 2^{16}\)

Vậy \(A>B\)

Câu b : Ta có :

\(A=4\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(=\dfrac{8\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)}{2}\)

\(=\dfrac{\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)}{2}\)

\(=\dfrac{\left(3^4-1\right)\left(3^4+1\right)...\left(3^{64}+1\right)}{2}\)

\(=\dfrac{...\left(3^{64}-1\right)\left(3^{64}+1\right)}{2}\)

\(=\dfrac{3^{128}-1}{2}< 3^{128}-1\)

Vậy \(A< B\)

28 tháng 9 2018

Xét biểu thức A

\(A=8\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(=\left(3^4-1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(...=\left(3^{64}-1\right)\left(3^{64}+1\right)=3^{128}-1\)

Vậy \(A=B\)

6 tháng 7 2016

\(S=4\cdot\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\cdot...\cdot\left(3^{64}+1\right)\)

\(\left(3^2-1\right)S=4\cdot\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\cdot...\cdot\left(3^{64}+1\right)\)

\(8S=4\cdot\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\cdot...\cdot\left(3^{64}+1\right)\)

\(2S=\left(3^8-1\right)\left(3^8+1\right)\cdot...\cdot\left(3^{64}+1\right)\)

...

\(2S=3^{128}-1\)

Vậy S < 3128 - 1

1. 2006/987654321 + 2007/246813579 = 2007/246813579 + 2006/987654321

=>

2.

3 - (5.3/8 + X - 7 . 5/24) : 6 . 2/3 =2

3 - (15/8 + X - 35/24) : 4 = 2

3 - (15/8 + X - 35/24) = 2 . 4

3 - (15/8 + X - 35/24) = 8

15/8 + X - 35/24 = 3 - 8

15/8 + X - 35/24 = -5

15/8 + X = -5 + 35/24

15/8 + X = -85/24

X = -85/24 - 15/8

X = -65/12

8 tháng 8 2016

Chính xác không bạn

14 tháng 7 2018

\(A=4\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(=\frac{1}{2}\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)

\(=\frac{1}{2}\left(3^4-1\right)\left(3^4+1\right)....\left(3^{64}+1\right)\)

                          \(.........\)

\(=\frac{1}{2}\left(3^{168}-1\right)\)\(< \)\(3^{168}-1\)

\(\Rightarrow\)\(A< B\)

17 tháng 7 2018

Tại sao 4 lại trở thành 2 vậy. Giải thích giúp mình nhé.

b: A=1/3+1/9+...+1/3^10

=>3A=1+1/3+...+1/3^9

=>A*2=1-1/3^10=(3^10-1)/3^10

=>A=(3^10-1)/(2*3^10)

c: C=3/2+3/8+3/32+3/128+3/512

=>4C=6+3/2+...+3/128

=>3C=6-3/512

=>C=1023/512

d: A=1/2+...+1/256

=>2A=1+1/2+...+1/128

=>A=1-1/256=255/256