X+ X x1/2 =3/4
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x+4/7=3/4 x-3/4=2/5 x x 2/3=3/4x1/2
x=3/4-4/7 x=2/5+3/4 x x2/3=3/8
x=21/28-16/28 x=8/20+15/20 x=3/8:2/3
x=5/28 x=23/20 x=9/16
1. Đề:...........
<=> x = 3/4 - 4/7
<=> x = 5/28
Vậy x = 5/28
2. Đề:............
<=> x = 2/5 + 3/4
<=> x = 23/20
Vậy x = 23/20
3. Đề:..........
<=> x. 2/3 = 3/8
<=> x = 3/8. 3/2
<=> x = 9/16
Vậy x = 9/16
Đặt \(t=2^x\)
Phương trình sẽ trở thành:
\(-t^2+3t-2=0\)
=>\(\left(t^2-3t+2\right)=0\)
=>\(\left(t-1\right)\left(t-2\right)=0\)
=>\(\left[{}\begin{matrix}t=1\\t=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2^x=1\\2^x=2\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
\(x_1+x_2=0+1=1\)
\(x\)là dấu nhân hả bạn? Nếu vậy thì mk làm cho nhé
\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{20}\right)\)
\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.......\cdot\frac{17}{18}\cdot\frac{18}{19}\cdot\frac{19}{20}=\frac{1}{20}\)
Vậy \(A=\frac{1}{20}\)
\(B=1\frac{1}{2}\cdot1\frac{1}{3}\cdot1\frac{1}{4}\cdot........\cdot1\frac{1}{2005}\cdot1\frac{1}{2006}\cdot1\frac{1}{2007}\)
\(B=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot......\cdot\frac{2006}{2005}\cdot\frac{2007}{2006}\cdot\frac{2008}{2007}=\frac{2008}{2}=1004\)
Vậy \(B=1004\)
DẤU CHẤM LÀ DẤU NHÂN
a,
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{19}{20}=\frac{1}{20}\)
b, \(1\frac{1}{2}.1\frac{1}{3}....1\frac{1}{2017}=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}=\frac{2018}{2}=1009\)
\(\frac{1}{1}\cdot\frac{1}{2}+\frac{1}{2}\cdot\frac{1}{3}+\frac{1}{3}\cdot\frac{1}{4}+\frac{1}{4}\cdot\frac{1}{5}+\frac{1}{5}\cdot\frac{1}{6}=\)
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}=\)
\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}=\)
\(\frac{1}{1}-\frac{1}{6}=\frac{5}{6}\)
k nha gõ mỏi tay lắm
\(x\cdot3:x+2\cdot6:4+x:0,5+0,25+x\cdot1=35\)
=>\(3+3+2x+0,25+x=35\)
=>3x+6,25=35
=>3x=35-6,25=28,75
=>\(x=\dfrac{28.75}{3}=\dfrac{115}{12}\)
\(\Leftrightarrow\left(\dfrac{3}{4}\right)^x.\left(\dfrac{4}{3}\right)^{\dfrac{4}{x}}=\dfrac{9}{16}\)
\(\Rightarrow\left(\dfrac{3}{4}\right)^x.\left(\dfrac{3}{4}\right)^{-\dfrac{4}{x}}=\left(\dfrac{3}{4}\right)^2\)
\(\Rightarrow\left(\dfrac{3}{4}\right)^{x-\dfrac{4}{x}}=\left(\dfrac{3}{4}\right)^2\)
\(\Rightarrow x-\dfrac{4}{x}=2\)
\(\Rightarrow x^2-2x-4=0\)
Viet: \(x_1+x_2=2\)
Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để được hỗ trợ tốt hơn.
\(x+\dfrac{x}{2}=\dfrac{3}{4}\)
\(\dfrac{2x}{2}+\dfrac{x}{2}=\dfrac{3}{4}\)
\(\dfrac{3x}{2}=\dfrac{3}{4}\)
\(3x.4=2.3\)
\(12x=6\)
\(x=\dfrac{1}{2}\)
\(x+x\times\dfrac{1}{2}=\dfrac{3}{4}\)
\(x\times\left(1+\dfrac{1}{2}\right)=\dfrac{3}{4}\)
\(x\) \(\times\) \(\dfrac{3}{2}\) \(=\) \(\dfrac{3}{4}\)
\(x\) \(=\dfrac{3}{4}:\dfrac{3}{2}\)
\(x\) \(=\dfrac{1}{2}\)