65 - 4x+2 = 20140
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1: =>\(5^{2x-3}=5^2\cdot3+5^2\cdot2=5^2\cdot5=5^3\)
=>2x-3=3
=>2x=6
=>x=3
2: \(41-2^{x+1}=9\)
=>\(2^{x+1}=32\)
=>x+1=5
=>x=4
3: =>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
\(5^{2x-3}-2.5^2=5^2.3\\ 5^{2x-3}=5^2.3+5^2.2\\ 5^{2x-3}=5^2.\left(3+2\right)\\ 5^{2x-3}=5^2.5\\ 5^{2x-3}=5^3\\ \Rightarrow2x-3=3\\ 2x=3+3\\ 2x=6\\ x=\dfrac{6}{2}\\ Vậy:x=3\)
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a, 1230 : 3(x – 20) = 10
3(x – 20) = 123
x – 20 = 41
x = 61
b, 250 – 10.(24 – 3x):15 = 244
10.(24 – 3x):15 = 6
10.(24 – 3x) = 90
24 – 3x = 9
3x = 15
x = 5
c, 4 x 3 + 15 = 47
4 x 3 = 32
x 3 = 8 = 2 3
x = 2
d, 65 - 4 x + 2 = 2014 0
65 - 4 x + 2 = 1
4 x + 2 = 64 = 4 3
x + 2 = 3
x = 1
e, 4 . 2 x - 3 = 125
4 . 2 x = 128
2 x = 32 = 2 5
x = 5
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a) 52x - 3 - 2 . 52 = 52 . 3
x - 3/52 - 2 = 3
x = 3 + 2 + 3/52
x = 263/52
b) 740 / (x + 10) = 102 - 2 . 13
740 / (x + 10) = 76
x + 10 = 740 / 76
x + 10 = 185/19
x = 185/19 - 10
x = -5/19
c) 65 - 4x + 2 = 20140
65 - 4x = 20140 - 2
65 - 4x = 20138
4x = 65 - 20138
4x = -20073
x = -20073/4
d) 120 + 2 . (3x - 17) = 214
60 + 3 . x - 17 = 107
20 + x - 17/3 = 107/3
20 + x = 107/3 + 17/3
20 + x = 124/3
x = 124/3 - 20
x = 64/3
e) 41 - 2x + 1 = 9
42 - 2x = 9
21 - x = 9/2
x = 21 - 9/2
x = 33/2
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Mình xin lỗi nhé, mình ghi đề saii đáng lẽ phải là (-2^2014) chứ không phải (-2^20140 nha các bạn.
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(4x - 28) : 2 = 9² - 65
(4x - 28) : 2 = 81 - 65
(4x - 28) : 2 = 16
4x - 28 = 16 . 2
4x - 28 = 32
4x = 32 + 28
4x = 60
x = 60 : 4
x = 15
(4\(x\) - 28) : 2 = 92 - 65
(4\(x\) - 28 ) : 2 = 81 - 65
(4\(x\) - 28) : 2 = 16
4\(x\) - 28 = 16 x 2
4\(x\) - 28 = 32
4\(x\) = 32 + 28
4\(x\) = 60
\(x\) = 60 : 4
\(x\) = 15
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án: D
65− 4 x + 2 = 2020 0
65− 4 x + 2 =1
4 x + 2 =65-1
4 x + 2 =64
4 x + 2 =43
x + 2 =3
x =3 - 2
x =1
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a) \(8x+56:14=60\)
\(\Rightarrow8x+4=60\)
\(\Rightarrow8x=56\)
\(\Rightarrow x=\dfrac{56}{8}\)
\(\Rightarrow x=7\)
b) Mình làm rồi nhé !
c) \(41-2^{x+1}=9\)
\(\Rightarrow2^{x+1}=41-9\)
\(\Rightarrow2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
d) \(3^{2x-4}-x^0=8\)
\(\Rightarrow3^{2x-4}-1=8\)
\(\Rightarrow3^{2x-4}=9\)
\(\Rightarrow3^{2x-4}=3^2\)
\(\Rightarrow2x-4=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
g) \(65-4^{x+2}=2014^0\)
\(\Rightarrow65-4^{x+2}=1\)
\(\Rightarrow4^{x+2}=64\)
\(\Rightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
i) \(120+2\left(4x-17\right)=214\)
\(\Rightarrow2\left(4x-17\right)=214-120\)
\(\Rightarrow2\left(4x-17\right)=94\)
\(\Rightarrow4x-17=47\)
\(\Rightarrow4x=47+17\)
\(\Rightarrow4x=64\)
\(\Rightarrow x=16\)
a: \(8x+56:14=60\)
=>8x+4=60
=>8x=60-4=56
=>x=56/8=7
b: \(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
=>\(5^{2x-3}=5^2\cdot3+2\cdot5^2=5^3\)
=>2x-3=3
=>2x=6
=>x=3
c: \(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>x+1=5
=>x=4
d: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}-1=8\)
=>\(3^{2x-4}=8+1=9\)
=>2x-4=2
=>2x=6
=>x=3
g: \(65-4^{x+2}=2014^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
i: 120+2(4x-17)=214
=>2(4x-17)=214-120=94
=>4x-17=94/2=47
=>4x=64
=>\(x=\dfrac{64}{4}=16\)
65 - 4^x+2 = 1
4^x . 4^2 =65 - 1
4^x . 16 = 64
4^x =64 : 16
4^x = 4
=>x=1
vậy x=1
\(65-4^{x+2}=2014^0\)
\(\Leftrightarrow65-4^{x+2}=1\)
\(\Leftrightarrow4^{x+2}=64\)
\(\Leftrightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)\(\Rightarrow x=1\)