Tìm x : a) \(\frac{3x+2}{-4x+5}\)=\(\frac{-4}{3}\) c) \(\frac{\left(2x+1\right)}{5}=\frac{3}{2x-1}\) e)\(\frac{\left|6x+1\right|}{4}=\frac{2}{4}\)b) \(\frac{2.\left|x\right|+5}{-4x+3}\)=\(\frac{-5}{4}\) d)\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\) g) \(\frac{\left|3x-5\right|}{3}=\frac{2\left|x\right|}{4}\)P/S : HuHU T_T Giúp mk với T_T 1 câu thôi cx đc T_T AI giúp mk sẽ tik 6 tik nhé ^^ Thanks mng trước ạ...
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Tìm x :
a) \(\frac{3x+2}{-4x+5}\)=\(\frac{-4}{3}\) c) \(\frac{\left(2x+1\right)}{5}=\frac{3}{2x-1}\) e)\(\frac{\left|6x+1\right|}{4}=\frac{2}{4}\)
b) \(\frac{2.\left|x\right|+5}{-4x+3}\)=\(\frac{-5}{4}\) d)\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\) g) \(\frac{\left|3x-5\right|}{3}=\frac{2\left|x\right|}{4}\)
P/S : HuHU T_T Giúp mk với T_T 1 câu thôi cx đc T_T AI giúp mk sẽ tik 6 tik nhé ^^ Thanks mng trước ạ T_T
a) \(\frac{3x+2}{-4x+5}=-\frac{4}{3}\left(ĐKXĐ:x\ne\frac{5}{4}\right)\)
\(\Rightarrow3\left(3x+2\right)=-4\left(-4x+5\right)\)
\(\Leftrightarrow9x+6=16x-20\)
\(\Leftrightarrow7x=26\)
\(\Leftrightarrow x=\frac{26}{7}\)
b) \(\frac{2\left|x\right|+5}{-4x+3}=-\frac{5}{4}\)(Thôi bài sau tự tìm đkxđ nhá)
\(\Rightarrow8\left|x\right|+20=20x-15\)
\(\Leftrightarrow8\left|x\right|-20x+35\)\(\left(1\right)\)
TH1: Nếu \(x\ge0\)thì \(\left(1\right)\Leftrightarrow8x-20x+35=0\Leftrightarrow x=\frac{35}{12}\left(tm\right)\)
TH2: Nếu \(x< 0\)thì \(\left(1\right)\Leftrightarrow-8x-20x+35=0\Leftrightarrow x=\frac{35}{28}\left(ktm\right)\)
Vậy x=35/12
c)\(\frac{2x+1}{5}=\frac{3}{2x-1}\)
\(\Rightarrow4x^2-1=15\)
\(\Leftrightarrow4x^2=16\)
\(\Leftrightarrow x^2=4\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-2\end{cases}}\)
d)\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)
\(\Leftrightarrow x^2+4x+3=x^2+4,5x+2\)
\(\Leftrightarrow0,5x=1\)
\(\Leftrightarrow x=2\)
e) \(\frac{\left|6x+1\right|}{4}=\frac{2}{4}\)
\(\Leftrightarrow\left|6x+1\right|=2\)
\(\Leftrightarrow\orbr{\begin{cases}6x+1=2\\6x+1=-2\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{6}\\x=-\frac{1}{2}\end{cases}}}\)
g)\(\frac{\left|3x-5\right|}{3}=\frac{\left|x\right|}{2}\)
\(\Leftrightarrow\frac{\left|3x-5\right|}{\left|x\right|}=\frac{3}{4}\)
\(\Leftrightarrow\left|\frac{3x-5}{x}\right|=\frac{3}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{3x-5}{x}=\frac{3}{4}\\\frac{3x-5}{x}=-\frac{3}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{20}{9}\\x=\frac{4}{3}\end{cases}}}\)
Mỏi tay quá, xin tý cho sảng khoái nào!!
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Hôm nay tặng bn 3 k , ngày mai mk tặng tiếp 3 k nx nhé ^^ Thanks bn nhiều lắm !