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29 tháng 3 2018

My school is called Vinh Thanh secondary school. My school is very clean and beautiful, teachers and students are very innocent, fun, friendly and hospitable.There are seven hundred students and seventy-five  teachers. There are 25 rooms in the school. Fifteen rooms are for classes, two room is for the teachers, a special room for the Head Teacher and other room. The results of the school is good. . They are high qualified teacher. They teach us with pleasure. They loves us their own children. There is a big play ground in front of the school. I love my school very much.

Chúc bn hk tốt !

29 tháng 3 2018

Bài này nữa nè :

I am a student at Phuc Yen Secondary school. My school is very big and more beautiful. At school, there are many students and teachers. The teachers are very nice andardor.They give me many many books and lessons. Everdday, I go to scool and meet my friends. We try to learn to become good student. We enjoy reading, playing, learning, helping together. In the scholl, I study so much, math, science, History, English , Vietnamese,... 
I English, Chemistry, math. I can sleep when I study. I try alot, if I lazy, my teachers are sad. I love all the day for school and love my teachers so much. Because not people don't love their school. I love it and I know It's love us too. I love my school, my friends, my teachers very much. I can not forget this beloved high school. I will try study to worthy my teachers, my school.

Chúc bn hk tốt !

13 tháng 7 2021

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21 tháng 10 2016

Bài 2:

Đặt \(\frac{a}{b}=\frac{c}{d}=k\Rightarrow\begin{cases}a=kb\\c=kd\end{cases}\)

=> \(\frac{5a+3b}{5a-3b}=\frac{5kb+3b}{5kb-3b}=\frac{b\left(5k+3\right)}{b\left(5k-3\right)}=\frac{5k+3}{5k-3}\left(1\right)\)

\(\frac{5c+3d}{5c-3d}=\frac{5kd+3d}{5kd-3d}=\frac{d\left(5k+3\right)}{d\left(5k-3\right)}=\frac{5k+3}{5k-3}\left(2\right)\)

Từ (1) và (2) => \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)

21 tháng 10 2016

Bài 3:

Đặt \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}=k\)

=> \(\frac{a}{b}.\frac{b}{c}.\frac{c}{d}=k^3\)

=> \(\frac{a}{d}=k^3\) (1)

Lại có: \(\frac{a+b+c}{b+c+d}=\frac{a}{b}=\frac{b}{c}=\frac{c}{d}=k\)

=> \(\left(\frac{a+b+c}{b+c+d}\right)^3=k^3\) (2)

Từ (1) và (2) => \(\frac{a}{d}=\left(\frac{a+b+c}{b+c+d}\right)^3\)

7 tháng 9 2016

Bạn cố chụp đi

7 tháng 9 2016

Mình ko chụp được khocroi

2 tháng 9 2021

hình bé quá

2 tháng 9 2021

sin 650=cos 350
\(cos70^0=sin30^0\)
\(tan80^0=cot20^0\)
\(cot68^0=tan32^0\)

30 tháng 9 2021

\(1,M=\left(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\right)\cdot\dfrac{2013}{2012}\\ M=\left(\dfrac{2\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{\dfrac{7}{2}\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}\right)}\right)\cdot\dfrac{2013}{2012}\\ M=\left(\dfrac{2}{7}-\dfrac{2}{7}\right)\cdot\dfrac{2013}{2012}=0\)

\(\left|x^2+\left|x-2\right|\right|=x^2+2021\\ \Leftrightarrow\left[{}\begin{matrix}x^2+\left|x-2\right|=x^2+2021\\x^2+\left|x-2\right|=-x^2-2021\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left|x-2\right|=2021\\\left|x-2\right|=-2x^2-2021\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x-2=\pm2021\\x\in\varnothing\left(-2x^2-2021< 0\right)\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2023\\x=-2019\end{matrix}\right.\)

\(3,\\ A=\left(x-\dfrac{2}{5}\right)^2+\left(y+20\right)^{10}+2022\ge2022\\ A_{min}=2022\Leftrightarrow\left\{{}\begin{matrix}x-\dfrac{2}{5}=0\\y+20=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{5}\\y=-20\end{matrix}\right.\)

 

30 tháng 9 2021

Thanks bạn haha

12 tháng 10 2021

Bài 1: 

Cả ba cái đều đúng

12 tháng 10 2021

Cảm ơn bạn!