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a) Ta có : 3n+6 chia hết cho 3n+6
=>2(3n+6) chia hết cho 3n+6
=> 6n+3-6n+12 chia hết cho 3n+6
-9 chia hết cho 3n+6
=> 3n+6 thuộc Ư(-9)={1,-1,3,-3,9,-9}
3n={-5,-7,-3,-9,3,-15}
n={-1,-3,1,-5}
a) n không có giá trị
b) n = 2
c) n= 6 ;8
d)n khong có giá trị
e) n= 3
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a, Ta có : \(\text{n + 5 = (n - 1)+6}\)
Vì \(\text{(n-1) ⋮ n-1}\)
Nên để \(\text{n+5 ⋮ n-1}\)⋮ `n-1`
Thì \(\text{6 ⋮ n-1}\)
\(\Rightarrow\) \(\text{n - 1 ∈ Ư(6)}\)
\(\Rightarrow\) \(\text{n - 1 ∈}\) \(\left\{\text{±1;±2;±3;±6}\right\}\)
\(\Rightarrow\) \(\text{n ∈}\) \(\left\{\text{0;-1;-2;-5;2;3;4;7}\right\}\) \(\text{( TM )}\)
\(\text{________________________________________________________}\)
b, Ta có : \(\text{2n-4 = (2n+4)- 8 = 2(n+2) - 8}\)
Vì \(\text{2(n+2) ⋮ n+2}\)
Nên để \(\text{2n-4 ⋮ n+2}\)
Thì \(\text{8 ⋮ n+2}\)
\(\Rightarrow\) \(\text{n + 2 ∈ Ư(8)}\)
\(\Rightarrow\) \(\text{n + 2 ∈}\) \(\left\{\text{±1;±2;±4;±8}\right\}\)
\(\Rightarrow\) \(\text{n ∈}\) \(\left\{\text{-3;-4;-6;-10;-1;0;2;6}\right\}\) ( TM )
\(\text{_________________________________________________________________ }\)
c, Ta có :\(\text{ 6n + 4 = (6n + 3) +1 = 3(2n+1) + 1}\)
Vì \(\text{3(2n+1) ⋮ 2n+1}\)
Nên để\(\text{ 6n+4 ⋮ 2n+1}\)
Thì \(\text{1 ⋮ 2n+1}\)
\(\Rightarrow\) \(\text{2n + 1 ∈ Ư(1)}\)
\(\Rightarrow\) \(\text{2n + 1 ∈}\) \(\left\{\text{±1}\right\}\)
\(\Rightarrow\) \(\text{2n ∈}\) \(\left\{\text{-2;0}\right\}\)
\(\Rightarrow\) \(\text{n ∈}\) \(\left\{\text{-1;0}\right\}\) ( TM )
\(\text{_______________________________________}\)
Ta có : \(\text{3 - 2n = -( 2n - 3 ) = -( 2n + 2 ) + 5 = -2( n+1)+5}\)
Vì \(\text{-2(n+1) ⋮ n+1}\)
Nên để \(\text{3-2n ⋮ n+1}\)
Thì\(\text{ 5 ⋮ n + 1}\)
\(\Rightarrow\) \(\text{n + 1 ∈}\) \(\left\{\text{±1;±5}\right\}\)
\(\Rightarrow\) \(\text{n ∈}\) \(\text{-2;-6;0;4}\) ( TM )
n+ 9 \(⋮n-2\)
mà n - 2 \(⋮n-2\)
= n -2 +11 \(⋮n-2\)
=> 11 \(⋮n-2\)
n -2 \(\inư\left(11\right)\in1,11\)
Ta có bảng:
| n-2 | 1 | 11 |
| n | 3 | 13 |
Vậy x = 3; 13
a, n+5 chia hết cho n-1 => n-1+6 chia hết cho n-1 => 6 chia hết cho n-1 hay n-1 thuộc Ư(6)
=> n-1={1,-1,2,-2,3,-3,6,-6}
=>n={2,0,3,-1,4,-2,7,-5}
Các TH khác tương tự nk
b, 2n-4=2(n+2)-8
c, 6n+4=3(2n+1)+1