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11+11=(1+1).(1+1)=4
12+13=(1+2).(1+3)=3.4=12
21+14=(1+2)(1+4)=3.5=15
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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a,= ( 1/14 + 13/14 ) + ( 4/11 + 14/22 )
= 1 + 1
= 2
b, = ( 2/26 + 12/13 ) + (3/4 + 25/100 ) + ( 4/7 + 9/21)
= 1 + 1 + 1
= 3
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Ta có: 11 + 11 = (1+1) . (1+1) = 2 . 2 = 4
12 + 13 = (1+2) . (1+3) = 3 . 4 = 12
=> 21 + 14 = (2+1) . (1+4) = 3 . 5 = 15
ta co 1+1=2
=>11+11=2*2=4
1+2=3
1+3=4
=>12+13=3*4
2+1=3
1+4=5
=>21+14=3*5=15