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\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
\(a,5x-5^2=3x+25\)
\(5x-3x=25+5^2\)
\(2x=50\)
\(x=50:2\)
\(x=25\)
\(b,3x+69:23=2x-108:36\)
\(3x+3=2x-3\)
\(3x-2x=-3-3\)
\(x=-6\)
Học tốt
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.
a, bổ sung đề
\(\dfrac{29-x}{21}+1+\dfrac{27-x}{23}+1+\dfrac{25-x}{25}+1+\dfrac{23-x}{27}+1+\dfrac{21-x}{29}+1=0\)
\(\Leftrightarrow\dfrac{50-x}{21}+\dfrac{50-x}{23}+\dfrac{50-x}{25}+\dfrac{50-x}{27}+\dfrac{50-x}{29}=0\)
\(\Leftrightarrow\left(50-x\right)\left(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\ne0\right)=0\Leftrightarrow x=50\)
a) (x – 45).27 = 0
=> x - 45 = 0
=> x = 45
b) 23.(42- x) = 23
=> 42- x = 1
=> x = 41
c. 3x – 5=7
=> 3x = 12
=> x = 4
e. 15 – 5x=10
=> 5x = 5
=> x = 1
\(\left(x-5\right)-27=18\)
\(x-5=45\)
\(x=50\)
vậy \(x=50\)
b) \(\left(3x-2^3\right).25=250\)
\(3x-8=10\)
\(3x=18\)
\(x=6\)
vậy \(x=6\)
c) \(108⋮x\)\(\Rightarrow x\inƯ\left(108\right)\) \(\Rightarrow x\in\left\{1;2;4;...;108\right\}\)
những ý sau làm tương tự
a)(x-5)-27=18
x-5=45
x=50
b)\(\left(3x-2^3\right).25=250\)
\(3x-2^3=10\)
\(3x=18\)
\(x=6\)