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2x –35 = 15
2x = 15 + 35
2x = 50
x = 50 : 2
x = 25.
Vậy x = 25.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, x = -8 - 3 = -11
b, 35 + x = 27 + 12 = 39
=> x = 39 - 35 = 4
c, 2x = 31 - 15 = 16
=> x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
X + (- 35 ) = 18
X - 35 = 18
X = 18 + 35
X = 53
Vậy X = 53
- 2x -(- 17)= 15
- 2x + 17 = 15
- 2x = 15 - 17
- 2x = - 2
x = - 2 : ( - 2 )
x = 1
Vậy x = 1
1) x+ (-35)=18
<=> x-35=18
<=> x=53
2) -2x-(-17)=15
<=> -2x+17=15
<=> -2x=-2
<=> x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x+(-35)=18
x-35=18
x=18+35
x=53
vậy x=53
b) -2x-(-17)=15
-2x+17=15
-2x=15-17
-2x=-2
x=-2:(-2)
x=1
vậy x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có: 770:[ ( 20x+10 ):x ] = 35
=>(20x+10):x =770:35
=>(20x+10):x =22
=>20x+10=22x
=>20x+10=20x .2x
=>10=2x
=>x=10:2
=.x=5
b,Ta có: 5x+15-2x=65
=>5x-2x+15=65
=>3x+15=65
=>3x=50
x=50/3
Chúc bạn làm bài tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a.\(3+x=-8\)
\(x=-8-3\)
\(x=-11\)
b.\(\left(35+x\right)-12=27\)
\(35+x=27+12\)
\(35+x=39\)
\(x=39-35\)
\(x=4\)
c.\(2^x+15=31\)
\(2^x=31-15\)
\(2^x=16\)
\(2^x=2^4\)
\(x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x= 10; y = 25
b) x + 2 y + 10 = 1 5 => ( x = 2).5 = ( y = 10).1=> 5.x + 10 = y + 10
=> 5.x = y mà y – 3.x = 2
Nên x = 1; y = 5
c) x = 20 ; y = 25
2x - 35 = 15
2x = 15 + 35
2x = 50
x = 50 : 2
x = 25
2x-35=15
<=> 2x=15+35
<=> 2x=50
<=> x=50:2
<=> x=25