![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 8899= (889)11
9988=(998)11
Vì (998)11<(999)11 mà (889)11<(999)11
=> 8899<9988
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^{333}=\left(5^3\right)^{111}=125^{111}\)
\(3^{555}=\left(3^5\right)^{111}=243^{111}\)
Vì 125 < 243 => 125111 < 243111
Vậy \(5^{333}<3^{555}\).
\(5^{333}=5^{3\cdot111}=\left(5^3\right)^{111}=125^{111}\)
\(3^{555}=3^{5\cdot111}=\left(3^5\right)^{111}=243^{111}\)
Vì \(125^{111}<243^{111}\)
Nên \(5^{333}<3^{555}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
A =\(\frac{1}{4^2}+\frac{1}{6^2}+...+\frac{1}{2018^2}\)
=> A <\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{2017.2019}\)
=> A < \(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2017}-\frac{1}{2019}\)
=> A < \(\frac{1}{3}-\frac{1}{2019}\)
=> A < 1
=> A < 99