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25 tháng 9 2017

Ta có : \(\left(x-5\right)^4=\left(x-5\right)^6\)

\(\Rightarrow\left(x-5\right)^4-\left(x-5\right)^6=0\)

\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^4=0\\1-\left(x-5\right)^2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^2=1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=5\\\left(x-5\right)=-1;1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=4;6\end{cases}}\)

Vậy x = {4;5;6}.

b) Ta có : ax = a50 

=> x = 50 

d) Ta có : 1 + 2 + 3 + ..... + x = 222111

=> \(\frac{\left[\left(x-1\right):1+1\right]\left(x+1\right)}{2}=222111\)

=> \(\frac{x\left(x+1\right)}{2}=222111\)

=> x(x + 1) = 444222

=> x(x + 1) = 666.667

=> x = 666 

Vậy x = 666.

15 tháng 10 2021

\(a,A=1+3+3^2+...+3^{125}\\ \Rightarrow3A=3+3^2+3^3+...+3^{126}\\ \Rightarrow2A=3^{126}-1\\ \Rightarrow A=\dfrac{3^{126}-1}{2}\\ c,2A=3^{2x}-1\\ \Rightarrow3^{126}-1=3^x-1\\ \Rightarrow x=126\)

\(d,A=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{124}+3^{125}\right)\\ A=\left(1+3\right)+3^2\left(1+3\right)+...+3^{124}\left(1+3\right)\\ A=\left(1+3\right)\left(1+3^2+...+3^{124}\right)\\ A=4\left(1+3^2+...+3^{124}\right)⋮4\)

a: =>x=-7/6+5/8=-13/24

b: =>x=-14/25-3/4=-131/100

c: \(x=\dfrac{-33}{26}:\dfrac{-9}{13}=\dfrac{33}{26}\cdot\dfrac{13}{9}=\dfrac{11}{3}\cdot\dfrac{1}{2}=\dfrac{11}{6}\)

d: \(x=\dfrac{4}{9}:\dfrac{5}{3}=\dfrac{4}{9}\cdot\dfrac{3}{5}=\dfrac{12}{45}=\dfrac{4}{15}\)

19 tháng 3 2022

1/3

-32/15

19 tháng 3 2022

1/3

-32/15

19 tháng 1 2022

\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)

a: =>6/x=3/8

hay x=16

b: =>x/27=1/9

nên x=3

c: =>4/x=4/3

nên x=3

d: =>3/x-5=-4/x+2

=>3x+2=-4x+20

=>7x=18

hay x=18/7

a: \(x-\dfrac{1}{24}=-\dfrac{1}{8}+\dfrac{5}{6}\)

=>\(x-\dfrac{1}{24}=\dfrac{-3}{24}+\dfrac{20}{24}=\dfrac{17}{24}\)

=>\(x=\dfrac{17}{24}+\dfrac{1}{24}=\dfrac{18}{24}=\dfrac{3}{4}\)

b: \(\dfrac{5}{8}-x=\dfrac{1}{9}-\left(-\dfrac{5}{4}\right)\)

=>\(\dfrac{5}{8}-x=\dfrac{1}{9}+\dfrac{5}{4}=\dfrac{4+45}{36}=\dfrac{49}{36}\)

=>\(x=\dfrac{5}{8}-\dfrac{49}{36}=\dfrac{45}{72}-\dfrac{98}{72}=\dfrac{-53}{72}\)

c: \(\dfrac{5}{9}+\dfrac{x}{-1}=-\dfrac{1}{3}\)

=>\(\dfrac{5}{9}-x=-\dfrac{1}{3}\)

=>\(x=\dfrac{5}{9}+\dfrac{1}{3}=\dfrac{8}{9}\)

`(5x+1)=36/49`

`<=> 5x = 36/49-1`

`<=> 5x = -13/49`.

`<=> x = -13/245.`

Vậy `x = -13/245`.

`b, x-2/9 = 2/3`.

`<=> x = 2/3 + 2/9`

`<=> x = 8/9`.

Vậy `x = 8/9`.

 

c: (8x-1)^(2x+1)=5^(2x+1)

=>8x-1=5

=>8x=6

=>x=3/4

d: Sửa đề: (x-3,5)^2+(y-1/10)^4=0

=>x-3,5=0 và y-0,1=0

=>x=3,5 và y=0,1

26 tháng 1 2023

Bài 1:

\(\left(x^2+1\right)\times\left(x-4\right)>0\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x^2+1>0\\x-4>0\end{matrix}\right.\\\left\{{}\begin{matrix}x^2+1< 0\\x-4< 0\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x^2>-1\\x>4\end{matrix}\right.\\\left\{{}\begin{matrix}x^2< -1\\x< 4\end{matrix}\right.\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x^2>-1\\x>4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x>0\\x>4\end{matrix}\right.\) \(\Leftrightarrow x>4\)

Đề bài 2 là gì ạ?

Bài 2:

a: A=(x-2)^2+(y+3)^2>=0

Dấu = xảy ra khi x=2 và y=-3

b: B=(x-5)^2+(y-1)^2-5>=-5

Dấu = xảy ra khi x=5 và y=1

a: =6-6=0

b: \(=\dfrac{-5}{4}:\dfrac{2-7}{8}+\dfrac{3}{2}\cdot\dfrac{2-5}{6}\)

\(=\dfrac{-5}{4}\cdot\dfrac{8}{-5}+\dfrac{3}{2}\cdot\dfrac{-3}{6}\)

\(=2+\dfrac{-9}{12}=2-\dfrac{3}{4}=\dfrac{5}{4}\)

c: \(=2,5\cdot\left(-0,65\right)+1,5\left(-0,3-0,35\right)=-0,65\cdot4=-2,6\)

20 tháng 1 2016

cu the cach lam nha