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\(4\left(x-5\right)-2^3=2^4.3\)
\(\Rightarrow4x-20-8=48\)
\(\Rightarrow4x=76\Rightarrow x=19\)
4(x-5) - 2^3 =2^4.3
4(x-5)-2^3=16.3
4(x-5)-2^3=48
4(x-5)=48+2^3
4(x-5)=56
x-5=56:4
x-5=14
x=14+5
x=19
sai mong mn thông cảm nha
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\(4\cdot\left(5-x\right)-2^3=2^4\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=16\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=48\)
\(\Rightarrow4\cdot\left(5-x\right)=48+8\)
\(\Rightarrow4\cdot\left(5-x\right)=56\)
\(\Rightarrow5-x=56:4\)
\(\Rightarrow5-x=14\)
\(\Rightarrow x=5-14\)
\(\Rightarrow x=-9\)
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\(4\left(x-5\right)-23=24\cdot3\)
\(4\left(x-5\right)-23=72\)
\(4\left(x-5\right)=72+23\)
\(4\left(x-5\right)=95\)
\(x-5=\dfrac{95}{4}\)
\(x=\dfrac{95}{4}+5\)
\(x=\dfrac{115}{4}\)
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240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
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x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
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Ta có: \(\left(-\dfrac{3}{2}\right)^3+\dfrac{-49}{24}\cdot\dfrac{3}{14}-\left(\dfrac{5}{8}-\dfrac{27}{8}\right)\)
\(=\dfrac{-27}{8}+\dfrac{-7}{2}\cdot\dfrac{1}{8}-\dfrac{-22}{8}\)
\(=\dfrac{-27+22}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-5}{8}+\dfrac{-7}{16}\)
\(=\dfrac{-10}{16}+\dfrac{-7}{16}\)
\(=\dfrac{-17}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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3x-2 -24 . 32 = 32 . 3
<=> 3x-2 -216 = 27
<=> 3x-2 =243
<=> 3x-2 = 35
<=> x-2 = 5
<=> x = 7
\(3^{x-2}-24\cdot3^2=3^2\cdot3\)
\(3^{x-2}-24\cdot9=9\cdot3\)
\(3^{x-2}-216=27\)
\(3^{x-2}=27+216=243\)
\(\Rightarrow3^{x-2}=3^5\)
\(\Rightarrow x-2=5\)
\(\Rightarrow x=5+2=7\)
tk mk nha. ~CHÚC BẠN HỌC TỐT~
\(4\left(x-5\right)-16=24\cdot3\)
\(\Rightarrow4\left(x-5\right)-16=72\)
\(\Rightarrow4\left(x-5\right)=72+16\)
\(\Rightarrow4\left(x-5\right)=88\)
\(\Rightarrow x-5=\dfrac{88}{4}\)
\(\Rightarrow x-5=22\)
\(\Rightarrow x=22+5\)
\(\Rightarrow x=27\)
\(4.\left(x-5\right)-16=24.3\)
\(4.\left(x-5\right)-16=72\)
\(4.\left(x-5\right)=72+16\)
\(4.x-5=88\)
\(x-5=88:4\)
\(x-5=22\)
\(x=22+5\)
\(x=27\)