Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(x^2+2\left(x+1\right)^2+3\left(x-2\right)^2+4\left(x+3\right)^2\)
\(=x^2+2\left(x^2+2x+1\right)+3\left(x^2-4x+4\right)+4\left(x^2+6x+9\right)\)
\(=x^2+2x^2+4x+2+3x^2-12x+12+4x^2+24x+36\)
\(=10x^2+16x+50\)
a. (x + y)2 = x2 + 2xy + y2
b. (x - 2y)2 = x2 - 4xy - 4x2
c. (xy2 + 1)(xy2 - 1) = x2y4 - 1
d. (x + y)2(x - y)2 = (x2 + 2xy + y2)(x2 - 2xy + y2) = x4 - (2xy + y2)2 = x4 - (4x2y2 + y4) = x4 - 4x2y2 - y4
Chucs hocj toots
Câu 2:
a: \(x^2-4x+4=\left(x-2\right)^2\)
b: \(x^2+10x+25=\left(x+5\right)^2\)
d: \(9\left(x+1\right)^2-6\left(x+1\right)+1=\left(3x+2\right)^2\)
e: \(\left(x-2y\right)^2-8\left(x-2xy\right)+16x^2=\left(x-2y+4x\right)^2=\left(5x-2y\right)^2\)
\(x^2+\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2\)
\(=x^2+x^2+1+3x^2+4+4x^2+9\)
\(=x^2+x^2+1+3x^2+3+4x^2+9+1\)
\(=2x^2+1+3x^2+3+4x^2+9+1\)
Từ đây ghép x vào rồi tính nốt đẳng thức thôi nhé
\(x^2+2\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2\)
\(=x^2+2\left(x^2+2x+1\right)+3\left(x^2+4x+4\right)+4\left(x^2+6x+9\right)\)
\(=10x^2+40x+50\)
\(=\left(x^2+10x+25\right)+\left(9x^2+30x+25\right)\)
\(=\left(x+5\right)^2+\left(3x+5\right)^2\)
\(x^2+2\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2\)
\(=x^2+2\left(x^2+2x+1\right)+3\left(x^2+4x+4\right)+4\left(x^2+6x+9\right)\)
\(=x^2+2x^2+4x+2+3x^2+12x+12+4x^2+24x+36\)
\(=10x^2+40x+50\)
\(=\left(9x^2+30x+25\right)+\left(x^2+10x+25\right)\)
\(=\left(3x+2\right)^2+\left(x+5^2\right)\)
\(x^2+2\left(x+1\right)^2+3\left(x+2\right)^2+4\left(x+3\right)^2\)
\(=x^2+2\left(x^2+2x+1\right)+3\left(x^2+4x+4\right)+4\left(x^2+6x+9\right)\)
\(=x^2+2x^2+4x+2+3x^2+12x+12+4x^2+24x+36\)
\(=10x^2+40x+50\)
\(x^2+2\left(x+1\right)^2+3\left(x+1\right)^2+4\left(x+1\right)^2\)
\(=x^2+9\left(x+1\right)^2\)
\(=x^2+3^2.\left(x+1\right)^2\)
\(=x^2+\left(3x+3\right)^2\)
